android - 如何将信息传递到自定义 ArrayAdapter 的 getView 中？

Question

我的应用程序中有以下类:

public class Player implements Parcelable {
    private String name;
    private int playerColor;
    private int[] scores;
    ...
}

我如何告诉我的 ArrayAdapter 的 getView 方法在关联的 ListView 中显示得分数组的哪个元素？我想根据 Activity 中的信息在 ListView 中显示 player.name 字段以及 player.scores 数组的特定元素。

public class PlayerGameAdapter extends ArrayAdapter<Player> {
private ArrayList<Player> entries;
private Activity activity;

 public PlayerGameAdapter(Activity a, int viewResourceId, ArrayList<Player> entries) {
    super(a, viewResourceId, entries);
    this.entries = entries;
    this.activity = a;
}

public static class ViewHolder {
    public Button buttonName;
}

@Override
public View getView(int position, View convertView, ViewGroup parent) {
    View v = convertView;
    ViewHolder holder;
    if (v == null) {
        LayoutInflater vi =
                (LayoutInflater) activity.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        v = vi.inflate(R.layout.listview_row_player_game, null);
        holder = new ViewHolder();
        holder.buttonName = (Button) v.findViewById(R.id.buttonGamePlayerListName);
        v.setTag(holder);
    } else
        holder = (ViewHolder) v.getTag();

    final MiniGolfPlayer player = entries.get(position);
    if (player != null) {
        holder.buttonName.setText(player.getName() + " - " + player.scores[ELEMENT]);
    }
    return v;
}

Answer 1

将位置变量添加到您的玩家类。

public class Player implements Parcelable {
    private String name;
    private int playerColor;
    private int[] scores;
    private int position; // also add the get and set methods
}

在您的 Activity 中，您可以更改要为每个玩家单独显示的分数的位置。

((Player)entries.get(0)).setPosition(AnyValueYouWant);
((Player)entries.get(1)).setPosition(AnotherValue);

然后通知您的适配器刷新 ListView :

PlayerGameAdapter.notifyDataSetChanged();

这对你有用吗？或者你期待别的东西。