java - 我在 Eclipse 上的 Java 程序停止打印到控制台，但之前它工作正常

Question

我正在为一个类(class)开发 Pig Latin 翻译器。我的程序之前已经运行过；它在底部的 for 循环中从translatedWords 数组列表中打印出来。但最新版本不会在底部 for 循环中打印。我怀疑这是一个大括号，但我似乎找不到它。

package stringTest;

import java.util.ArrayList;

public class StringTest {

    public static void main(String[] args) {
        String userString = "THIS IS A STRING";

        // We might need to trim the string first it throws an error if           theres
    // white space around word
    // Making string lowercase, first
    userString = userString.toLowerCase();

    // Splitting up string into individual words
    String[] stringArray = userString.split(" ");
    ArrayList<String> translatedWords = new ArrayList<String>();

    // going through each string with foreach loop
    for (String ss : stringArray) {
        System.out.println("prints here in intial for loop");
        // pulling out the words that start with a vowel
        // since they just get "way" at the end
        if (ss.charAt(0) == 'a' || ss.charAt(0) == 'e'
                || ss.charAt(0) == 'i' || ss.charAt(0) == 'o'
                || ss.charAt(0) == 'u') {
            ss = ss.concat("way");
            translatedWords.add(ss);

        }

        // If the words don't start with a vowel
        // trying to figure out how to cut them at first vowel and
        // concatenate to end
        else {
            for (int i = 0; i < ss.length();) {
                if (ss.charAt(i) == 'a' || ss.charAt(i) == 'e'
                        || ss.charAt(i) == 'i' || ss.charAt(i) == 'o'
                        || ss.charAt(i) == 'u') {
                    ss = ss.substring(i, ss.length());
                    String sss = ss.substring(0, i + 1);
                    String ss44 = ss.substring(i + 1);
                    String ss33 = ss44 + sss;
                    ss33 = ss33 + "ay";
                    translatedWords.add(ss33);
                    System.out.println(ss33);
                    System.out.println("Why won't this print");
                    break; 

                }
            }

        }

        for (String fs : translatedWords) {
            System.out.print(fs.toString() + " ");
        }

       }
    }
}

Answer 1

这不是花括号，而是 for 循环无限运行

i 在 for 语句中或 for 内部永远不会递增

因此，if 条件将继续运行字符串的第一个字符，如果它不是元音，则字符串“this”将为 false，因此它永远不会进入 if 语句

  //for (int i = 0; i < ss.length();) {//no i++ implemented
  for (int i = 0; i < ss.length();i++) {
            if (ss.charAt(i) == 'a' || ss.charAt(i) == 'e'
                    || ss.charAt(i) == 'i' || ss.charAt(i) == 'o'
                    || ss.charAt(i) == 'u') {
                ss = ss.substring(i, ss.length());
                String sss = ss.substring(0, i + 1);
                String ss44 = ss.substring(i + 1);
                String ss33 = ss44 + sss;
                ss33 = ss33 + "ay";
                translatedWords.add(ss33);
                System.out.println(ss33);
                System.out.println("Why won't this print");
                break; 

            }
        }