java - 使用值对 ArrayList> 进行排序

Question

我的代码中有 Hashmap 的 ArrayList我很困惑我应该使用哪种排序方法？我的代码如下

arraylist = new ArrayList<HashMap<String, String>>();
            // Retrieve JSON Objects from the given URL address
            jsonobject = JSONFunctions
                        .getJSONfromURL("https://api.foursquare.com/v2/venues/search?    client_id=ACAO2JPKM1MXHQJCK45IIFKRFR2ZVL0QASMCBCG5NPJQWF2G&client_secret=YZCKUYJ1W    HUV2QICBXUBEILZI1DMPUIDP5SHV043O04FKBHL&v=20130815&ll=-34.678,138.87&radius=5000&section=coffee");

        try {
            // Locate the array name in JSON
            jsonarray = jsonobject.getJSONObject("response");

            JSONArray jsonSubarray = jsonarray.getJSONArray("venues");
            Log.v("Response Array", String.valueOf(jsonSubarray));



            for (int i = 0; i < jsonSubarray.length(); i++) {
                HashMap<String, String> map = new HashMap<String, String>();

                jsonobject = jsonSubarray.getJSONObject(i);
                // Retrive JSON Objects
                // Retrive JSON Objects

                Log.v("Store name", jsonobject.getString("name"));
                map.put("storeName", jsonobject.getString("name"));

                JSONObject locationObject = jsonobject.getJSONObject("location");
                Log.v("if condition",String.valueOf( locationObject.has("city")));
                if(locationObject.has("city"))
                {
                    map.put("city", locationObject.getString("city"));
                }
                else
                    map.put("city","N/A");

                double km = Double.valueOf(locationObject.getString("distance")) / 1000 ;
                Log.v("distance", String.valueOf(km));
                map.put("distance", String.valueOf(km));

                arraylist.add(map);

            }
        } catch (JSONException e) {
            Log.e("Error", e.getMessage());
            e.printStackTrace();
        }
        return null;
    }

这是我的 JSON 数据格式

"id": "4e321829d4c00077f657b8ec",
            "name": "TeAro Estate Wines",
            "contact": {},
            "location": {
                "lat": -34.670859098532766,
                "lng": 138.89067804714347,
                "distance": 2053,
                "cc": "AU",
                "city": "Williamstown",
                "state": "SA",
                "country": "Australia",
                "formattedAddress": [
                    "Williamstown SA",
                    "Australia"
                ]
            },
            "categories": [
                {
                    "id": "4bf58dd8d48988d14b941735",
                    "name": "Winery",
                    "pluralName": "Wineries",
                    "shortName": "Winery",
                    "icon": {
                        "prefix": "https://ss3.4sqi.net/img/categories_v2/food/winery_",
                        "suffix": ".png"
                    },
                    "primary": true
                }
            ],
        {
            "id": "4c454825f0bdd13a65c9cacc",
            "name": "Barossa Dam",
            "contact": {},
            "location": {
                "address": "Dam it",
                "lat": -34.645353,
                "lng": 138.848115,
                "distance": 4150,
                "cc": "AU",
                "city": "Sandy Creek",
                "state": "SA",
                "country": "Australia",
                "formattedAddress": [
                    "Dam it",
                    "Sandy Creek SA",
                    "Australia"
                ]
            },

我想按距离排序请给我一些关于我应该使用什么方法的建议我对数组列表和 HashMap 的数组列表感到困惑我如何使用 collection.sort 对我的数据进行排序。

我想根据 ArrayList 中的值进行排序。

Answer 1

使用比较器对其进行排序。

Comparator<HashMap<String, String>> distanceComparator = new Comparator<HashMap<String,String>>() {

    @Override
    public int compare(HashMap<String, String> o1, HashMap<String, String> o2) {
        // Get the distance and compare the distance.
        Integer distance1 = Integer.parseInt(o1.get("distance"));
        Integer distance2 = Integer.parseInt(o2.get("distance"));

        return distance1.compareTo(distance2);
    }
};

// And then sort it using collections.sort().
Collections.sort(arrayList, distanceComparator);