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java - 检查字符串中的单词是否在数组中

转载 作者:行者123 更新时间:2023-11-30 03:19:28 24 4
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我正在制作一个聊天机器人,我希望它检查您输入的任何单词是否与预定义列表中的单词匹配。

例如:我输入我很好,谢谢!
我有一个包含棒极了完美快乐的列表。
我希望程序检查列表中是否有 I'mgoodthanks! 等单词。

import java.util.Arrays;
import java.util.Random;
import java.util.Scanner;
import use.*;

public class welcome {


public static void say() {


}

public static void main(String[] args) {
wait.clean();
String input1 = "";
String name = "Antonio";
String surname = "Solana";
Scanner scanner1 = new Scanner(System.in);
String[] goodadj = {"good", "well", "awesome", "perfect", "adaptable", "adventurous", "affable", "affectionate", "agreeable", "ambitious", "amiable", "amicable", "amusing", "brave", "bright", "broad-minded", "calm", "careful", "charming", "communicative", "compassionate", "conscientious", "considerate", "convivial", "courageous", "courteous", "creative", "decisive", "determined", "diligent", "diplomatic", "discreet", "dynamic", "easygoing", "emotional", "energetic", "enthusiastic", "exuberant", "fair-minded", "faithful", "fearless", "forceful", "frank", "friendly", "funny", "generous", "gentle", "good", "gregarious", "hard-working", "happy", "helpful", "honest", "humorous", "imaginative", "impartial", "independent", "intellectual", "intelligent", "intuitive", "inventive", "kind", "loving", "loyal", "modest", "neat", "nice", "optimistic", "passionate", "patient", "persistent", "pioneering", "philosophical", "placid", "plucky", "polite", "powerful", "practical", "pro-active", "quick-witted", "quiet", "rational", "reliable", "reserved", "resourceful", "romantic", "self-confident", "self-disciplined", "sensible", "sensitive", "shy", "sincere", "sociable", "straightforward", "sympathetic", "thoughtful", "tidy", "tough", "unassuming", "understanding", "versatile", "warmhearted", "willing", "witty"};
String[] badadj = {"awful", "sad", "bad", "aggressive", "aloof", "arrogant", "belligerent", "big-headed", "bitchy", "boastful", "bone-idle", "boring", "bossy", "callous", "cantankerous", "careless", "changeable", "clinging", "compulsive", "conservative", "cowardly", "cruel", "cunning", "cynical", "deceitful", "detached", "dishonest", "dogmatic", "domineering", "finicky", "flirtatious", "foolish", "foolhardy", "fussy", "greedy", "grumpy", "gullible", "harsh", "impatient", "impolite", "impulsive", "inconsiderate", "inconsistent", "indecisive", "indiscreet", "inflexible", "interfering", "intolerant", "irresponsible", "jealous", "lazy", "Machiavellian", "materialistic", "mean", "miserly", "moody", "narrow-minded", "nasty", "naughty", "nervous", "obsessive", "obstinate", "overcritical", "overemotional", "parsimonious", "patronizing", "perverse", "pessimistic", "pompous", "possessive", "pusillanimous", "quarrelsome", "quick-tempered", "resentful", "rude", "ruthless", "sarcastic", "secretive", "selfish", "self-centred", "self-indulgent", "silly","sneaky", "stingy", "stubborn", "stupid", "superficial", "tactless", "timid", "touchy", "thoughtless", "truculent", "unkind", "unpredictable", "unreliable", "untidy", "untrustworthy", "vague", "vain", "vengeful", "vulgar", "weak-willed"};
String[] afirmation = {"ok", "okay", "yes", "well", "affirmative", "amen", "fine", "good", "okay", "true", "yeah", "all right", "aye", "beyond a doubt", "by all means", "certainly", "definitely", "even so", "exactly", "gladly", "good enough", "granted", "indubitably", "just so", "most assuredly", "naturally", "of course", "positively", "precisely", "sure thing", "surely", "undoubtedly", "unquestionably ", "very well", "willingly", "without fail", "yep star"};
String[] negation = {"no", "nope", "never", "nix", "absolutely not", "not at all", "no way", "by no means", "not by any means"};

Random rand = new Random();

int x = rand.nextInt((6 - 1) + 1) + 1;
String hi = "";
if (x == 1) {
hi = "Hey! Sup ";
}

if (x == 2) {
hi = "Nice to see you again ";
}

if (x == 3) {
hi = "You smell good today ";
}

if (x == 4) {
hi = "Kon'nichiwa ";
}

if (x == 5) {
hi = "I didn't heard you comming ";
}

if (x == 6) {
hi = "Wasssaaap ";
}

x = rand.nextInt((6 - 1) + 1) + 1;
String question1 = "";
if (x == 1) {
question1 = "How are you today boy?";
}

if (x == 2) {
question1 = "U good?";
}

if (x == 3) {
question1 = "You look good don't you? (I can't see you... sorry...)";
}

if (x == 4) {
question1 = "How are you feeling?";
}

if (x == 5) {
question1 = "How are you this beautiful day?";
}

if (x == 6) {
question1 = "Was your day good?";
}

x = rand.nextInt((6 - 1) + 1) + 1;
String joke = "";
if (x == 1) {
joke = "What's the difference between snowmen and snowladies? Snowballs.";
}

if (x == 2) {
joke = "I am a nobody, nobody is perfect, therefore I am perfect.";
}

if (x == 3) {
joke = "Siri. You should laugh, she is a joke.";
}

if (x == 4) {
joke = "Do you know the dentist who never agrees with the other nine? I think he is sleeping or something.";
}

if (x == 5) {
joke = "Why do farts smell? So deaf people can enjoy them too.";
}

if (x == 6) {
joke = "I asked God for a bike, but I know God doesn't work that way. So I stole a bike and asked for forgiveness.";
}

x = rand.nextInt((6 - 1) + 1) + 1;
String happy = "";
if (x == 1) {
happy = "What's the difference between snowmen and snowladies? Snowballs.";
}

if (x == 2) {
happy = "I am a nobody, nobody is perfect, therefore I am perfect.";
}

if (x == 3) {
happy = "Siri. You should laugh, she is a joke.";
}

if (x == 4) {
happy = "Do you know the dentist who never agrees with the other nine? I think he is sleeping or something.";
}

if (x == 5) {
happy = "Why do farts smell? So deaf people can enjoy them too.";
}

if (x == 6) {
happy = "I asked God for a bike, but I know God doesn't work that way. So I stole a bike and asked for forgiveness.";
}

x = rand.nextInt((6 - 1) + 1) + 1;
String sad = "";
if (x == 1) {
sad = "What's the difference between snowmen and snowladies? Snowballs.";
}

if (x == 2) {
sad = "I am a nobody, nobody is perfect, therefore I am perfect.";
}

if (x == 3) {
sad = "Siri. You should laugh, she is a joke.";
}

if (x == 4) {
sad = "Do you know the dentist who never agrees with the other nine? I think he is sleeping or something.";
}

if (x == 5) {
sad = "Why do farts smell? So deaf people can enjoy them too.";
}

if (x == 6) {
sad = "I asked God for a bike, but I know God doesn't work that way. So I stole a bike and asked for forgiveness.";
}



System.out.println(hi + name);
wait.one();
System.out.println(question1);
input1 = scanner1.next();
input1 = input1.toLowerCase();
String[] input2 = input1.split(" ");

if (Arrays.asList(goodadj).contains(input2) || Arrays.asList(afirmation).contains(input2)) {
System.out.println("Good for you!");
wait.one();
System.out.println("Do you want to tell me about it?");
input1 = scanner1.next();
input1 = input1.toLowerCase();
input2 = input1.split(" ");

if (Arrays.asList(goodadj).contains(input2) || Arrays.asList(afirmation).contains(input2)) {
input1 = scanner1.next();
System.out.println(happy);
}

if (Arrays.asList(goodadj).contains(input2) || Arrays.asList(afirmation).contains(input2)) {
input1 = scanner1.next();
System.out.println(sad);
}

}

if (Arrays.asList(badadj).contains(input2) || Arrays.asList(negation).contains(input2)) {
System.out.println("I'm sorry, I could help you if you want...");
input1 = scanner1.next();
input1 = input1.toLowerCase();

if (Arrays.asList(afirmation).contains(input2)) {
System.out.println(joke);
}

if (Arrays.asList(negation).contains(input2)) {
System.out.println("I understand");
}
}

else {
System.out.println("I don't really understand that...");
}


}

}这就是我尝试过的。 goodadj 是我要搜索的列表,good 是该列表中的输入单词。我可以使用任何我想要的东西,这个项目只是为了好玩。感谢所有提供帮助的人。

最佳答案

使用 .split("") 将输入值存储到数组中

String [] baseValues = {"Awesome", "Perfect", "Happy", "Good"};

Scanner scan = new Scanner();

String userInput = scan.nextLine();

String [] inputArray = userInput.split(" ");

这会给你这样的东西 [“我,我”,“很好”,“谢谢!”]

对于 inputArray 的每个值,循环遍历这些值并将其与每个基值进行比较。

获取输入的用户的输入,循环遍历数组中的值并查看他们为您提供的字符串是否包含其中的任何一个。

**免责声明,这些效率低下,使用哈希集将是最佳方式,这些响应特定于数组。

关于java - 检查字符串中的单词是否在数组中,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31688279/

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