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java - JAXB - 如何使用 Map 中的属性创建 XML 元素?

转载 作者:行者123 更新时间:2023-11-30 03:18:33 24 4
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我需要这样的东西-

<Token>
<HighLevel info-1="" info-2=""/>
<LowLevel>
<LowLevel info-key="" info-value=""/>
<LowLevel info-key="" info-value=""/>
....
</LowLevel>
</Token >

我有 LowLevel 元素的 Map,我想像上面的 XML 一样填充其条目。使用 JAXB 封装/绑定(bind)它的方法是什么?

最佳答案

您可以为此使用自定义适配器。示例

//Token.java
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlSeeAlso;
import javax.xml.bind.annotation.adapters.XmlAdapter;
import javax.xml.bind.annotation.adapters.XmlJavaTypeAdapter;

@XmlRootElement
class LowLevelToken {
@XmlAttribute(name = "info-key")
public String key;
@XmlAttribute(name = "info-value")
public String value;

private LowLevelToken() {}

public LowLevelToken(String key, String value) {
this.key = key;
this.value = value;
}
}

@XmlRootElement
class HighLevelToken {
@XmlAttribute(name = "info-1")
public String info1;
@XmlAttribute(name = "info-2")
public String info2;

private HighLevelToken() {}

public HighLevelToken(String info1, String info2) {
this.info1 = info1;
this.info2 = info2;
}
}

class TokenWrapper {
@XmlElement(name="LowLevel")
public List<LowLevelToken> tokens = new ArrayList<LowLevelToken>();
}

class TokenAdapter extends XmlAdapter<TokenWrapper, Map<String, String>> {
@Override
public TokenWrapper marshal(Map<String, String> lowlevelTokens)
throws Exception {
TokenWrapper wrapper = new TokenWrapper();
List<LowLevelToken> elements = new ArrayList<LowLevelToken>();
for (Map.Entry<String, String> property : lowlevelTokens.entrySet()) {
elements.add(new LowLevelToken(property.getKey(), property.getValue()));
}
wrapper.tokens = elements;
return wrapper;
}

@Override
public Map<String, String> unmarshal(TokenWrapper tokenWrapper) throws Exception {
Map<String, String> tokens = null;
if(tokenWrapper != null && tokenWrapper.tokens != null && !tokenWrapper.tokens.isEmpty()){
tokens = new HashMap<String, String>();
for(LowLevelToken token : tokenWrapper.tokens){
tokens.put(token.key, token.value);
}
}
return tokens;
}
}

@XmlRootElement(name = "Token")
public class Token {

HighLevelToken highLevel;
Map<String, String> lowLevel;

public HighLevelToken getHighLevel() {
return highLevel;
}

@XmlElement(name = "HighLevel")
public void setHighLevel(HighLevelToken highLevel) {
this.highLevel = highLevel;
}

public Map<String, String> getLowLevel() {
return lowLevel;
}

@XmlElement(name = "LowLevel")
@XmlJavaTypeAdapter(TokenAdapter.class)
public void setLowLevel(Map<String, String> lowLevel) {
this.lowLevel = lowLevel;
}
}

示例程序

import java.util.HashMap;

import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;

public class JAXBExample {
public static void main(String[] args) {
Token token = new Token();
token.setHighLevel(new HighLevelToken("1", "2"));
token.setLowLevel(new HashMap<String, String>() {{ put("LK1", "LV1"); put("LK2", "LV2"); put("LK2", "LV2"); }});
try {
JAXBContext jaxbContext = JAXBContext.newInstance(Token.class);
Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
jaxbMarshaller.marshal(token, System.out);
} catch (JAXBException e) {
e.printStackTrace();
}
}
}

这会生成

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<Token>
<HighLevel info-1="1" info-2="2"/>
<LowLevel>
<LowLevel info-key="LK2" info-value="LV2"/>
<LowLevel info-key="LK1" info-value="LV1"/>
</LowLevel>
</Token>

关于java - JAXB - 如何使用 Map 中的属性创建 XML 元素?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31920634/

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