java - 数组中包含开头和结尾元音的最长字符串

Question

我试图获取数组中以元音开头和结尾的最长字符串。当我运行代码时，每次循环后都会显示最长的值，但不会显示变量longest的最高值。

class xJava
{
public static void firstlastVowel (String theString)
{
    int index;
    int longest=0;
    char x = theString.charAt(index=0);
    char y = theString.charAt(theString.length()-1);
    int z = theString.length()-1;

    if(x == 'a' || x == 'e' || x == 'i' || x == 'o' || x == 'u')
    {
        if(y == 'a' || y == 'e' || y == 'i' || y == 'o' || y == 'u')
        {
            System.out.println(theString + " starts and ends with a vowel");

            if(z > longest)
            {
                longest = z;
                System.out.println("longest string is "+longest+" characters!");
            }
        }


    }
}



public static void main (String[] args)
{
    int index;
    String value;

    String[] things = {"abba", "orlando", "academia", "ape"};


    for(String thing : things)
    {
        firstlastVowel(thing);
    }

}

}

如何让变量longest仅包含最长字符串的长度？

输出是:

 abba starts and ends with a vowel
 longest string is 3 characters!
 orlando starts and ends with a vowel
 longest string is 6 characters!
 academia starts and ends with a vowel
 longest string is 7 characters!
 ape starts and ends with a vowel
 longest string is 2 characters!

Answer 1

啊，我应该知道不应该发布这个:

  String[] things = { "aa", "orrro", "academia", "ape" };
  int longest = Arrays.stream(things)
      .filter(s -> s.matches("^[aeiouy].*[aeiouy]$"))
      .map(String::length)
      .reduce(0, Math::max);
  System.out.println("longest string is " + longest + " characters!");

为什么以及如何运作留给读者作为练习。