c++ - 如何让 while 循环与数字生成器一起工作？

Question

因此，对于我的练习，我必须使用 srand 函数生成 1 到 100 之间的随机数。我让那部分开始工作，但随后我必须添加一个循环，以便用户在第一次尝试没有正确时可以再次猜测。我似乎无法使 while 循环工作。

我正在编写有关文本编辑的代码，并通过 mac 上的终端应用程序使用 Xcode 作为编译器。我正在尽最大努力使用编程术语——我是新手，所以如果有什么不对劲，那就是原因。

int main()
{
  srand(time(0));
  int randomNumber = 1 + (rand() % 100);
  int humanGuess;


  while (true)
  {
    cout << "Guess a number between 1 and 100!" << endl; 
    cin >> humanGuess;
    cin.ignore(1000, 10);

    if (humanGuess == randomNumber) break; 
    cout << "Great job. You got it! It's " << randomNumber << endl; 

    if (humanGuess >= randomNumber)
    cout << "Too high. Try again!" << endl;

    if (humanGuess <= randomNumber)
    cout << "Too low. Try again!" << endl;
  }//while 
}

没有错误消息，但编译不正确。这是我在终端上运行时不断得到的:

Guess a number between 1 and 100!
23
Great job. You got it! It's 55
Too low. Try again!
Guess a number between 1 and 100!
78
Great job. You got it! It's 55
Too high. Try again!
Guess a number between 1 and 100!

Answer 1

如问题所示，您的代码是(break 单独一行)

if (humanGuess == randomNumber)
    break;

cout << "Great job. You got it! It's " << randomNumber << endl; 

如果条件 humanGuess == randomNumber 为真，则使用 break 语句跳出循环。否则你无条件地打印“干得好...”。

您需要将打印作为if 语句主体的一部分，并在打印后break:

if (humanGuess == randomNumber)
{
    cout << "Great job. You got it! It's " << randomNumber << endl; 
    break;
}