java - 从文件转换十六进制字符串的输出错误

Question

我的代码输出有问题。我必须将十六进制字符串从文件转换为二进制，然后将该二进制转换为十进制。然后找到芯片中的RAM错误，我还没有编码。我现在主要担心的是，当我运行程序时，我的第一个结果是正确的，但对于其余 3 个十六进制到二进制输出，二进制字符串将自身附加到先前的二进制输出，并且它变成一个又长又错误的二进制字符串。

public static void main(String arg[]) throws IOException {
    Scanner infile = new Scanner(new File("RAMerrors.txt"));

    String result = "";
    String binVal; // the binary value of the Hex

    while (infile.hasNextLine()) {
        String line = infile.nextLine();
        Scanner input = new Scanner(line);
        String hex = input.next();

        for (int i = 0; i < hex.length(); i++) {
            char hexChar = hex.charAt(i);

            switch (hexChar) {
                case ('0'):
                    binVal = "0000";
                    break;
                case ('1'):
                    binVal = "0001";
                    break;
                case ('2'):
                    binVal = "0010";
                    break;
                case ('3'):
                    binVal = "0011";
                    break;
                case ('4'):
                    binVal = "0100";
                    break;
                case ('5'):
                    binVal = "0101";
                    break;
                case ('6'):
                    binVal = "0110";
                    break;
                case ('7'):
                    binVal = "0111";
                    break;
                case ('8'):
                    binVal = "1000";
                    break;
                case ('9'):
                    binVal = "1001";
                    break;
                case ('A'):
                    binVal = "1010";
                    break;
                case ('B'):
                    binVal = "1011";
                    break;
                case ('C'):
                    binVal = "1100";
                    break;
                case ('D'):
                    binVal = "1101";
                    break;
                case ('E'):
                    binVal = "1110";
                    break;
                case ('F'):
                    binVal = "1111";
                    break;
                default:
                    binVal = "invalid input";
                    break;
            }
            result += binVal;
        }
        System.out.println("Binary of " + hex + ":" + result);
        System.out.println("And the decimal is " + convertBin2Dec(result) + "\n");
    }
}

我的输出如下:

Binary of ABCDEFABC: 101010111100110111101111101010111100
And the decimal is 46118402748

Binary of 1A00D0000: 101010111100110111101111101010111100000110100000000011010000000000000000
And the decimal is 9223372036854775807

Binary of 7A0EDF301: 101010111100110111101111101010111100000110100000000011010000000000000000011110100000111011011111001100000001
And the decimal is 9223372036854775807

Binary of 3CDAEFFAD: 101010111100110111101111101010111100000110100000000011010000000000000000011110100000111011011111001100000001001111001101101011101111111110101101
And the decimal is 9223372036854775807

Answer 1

您没有在检查之间清除 result 变量。

如果您在 while 循环内声明 result，它应该可以解决您的问题。