c++ - 帮助更正源代码，使用模板

Question

我尝试编译发布的示例(C++ Service Providers)，但未能通过 VS8 VC9。我对模板的经验很少。
有什么建议吗？
坦克。

这些是错误:
dictionarySTL.cpp(40) : error C2663: 'std::_Tree<_Traits>::find' : 2 重载没有 'this' 指针的合法转换
dictionarySTL.cpp(48) : error C2679: binary '[' : no operator found which takes a right-hand operand of type 'const type_info *__w64 ' (or there are no acceptable conversion)

#include <typeinfo>
#include <map>
#include <string>
using namespace std;

class SomeClass
{
public:
    virtual ~SomeClass() {} // virtual function to get a v-table
};

struct type_info_less
{
    bool operator() (const std::type_info* lhs, const std::type_info* rhs) const
    {
        return lhs->before(*rhs) != 0;
    }
};

class TypeMap
{
    typedef map <type_info *, void *, type_info_less> TypenameToObject;
    TypenameToObject ObjectMap;

public:
    template <typename T> 
    T *Get () const
    {
        TypenameToObject::const_iterator iType = ObjectMap.find(&typeid(T));
        if (iType == ObjectMap.end())
            return NULL;
        return reinterpret_cast<T *>(iType->second);
    }
    template <typename T> 
    void Set(T *value) 
    {
        ObjectMap[&typeid(T)] = reinterpret_cast<void *>(value);
    }
};

int main()
{
    TypeMap Services;
    Services.Set<SomeClass>(new SomeClass());
    SomeClass *x = Services.Get<SomeClass>();
}

Answer 1

要编译此代码，请执行以下行:

typedef map<type_info *, void *, type_info_less> TypenameToObject;

应该是:

typedef map<const type_info *, void *, type_info_less> TypenameToObject;