gpt4 book ai didi

android - 如何解析和显示 json 数组中的 url 内容?

转载 作者:行者123 更新时间:2023-11-30 03:12:28 26 4
gpt4 key购买 nike

我在 jsonarray 中有一个图像,但像 "flag": [
“http://www.simplydecoded.com/wp-content/uploads/2013/02/Telangana2.jpg”
]

但不显示..

我正在使用 this解析数据的教程

我成功地解析了所有数据,但图像没有出现

我正在使用它来调用位于 json 数组中的图像,实际上它是一个 url..

JSONArray json_query_flag = c.getJSONArray("flag");

然后我一直跟着 remaning 来回 this问题..

它只是不重复的扩展..

我在下面使用了将图像下载到位图的部分

public class ImageLoader {

MemoryCache memoryCache = new MemoryCache();
FileCache fileCache;
private Map<ImageView, String> imageViews = Collections
.synchronizedMap(new WeakHashMap<ImageView, String>());
ExecutorService executorService;
// Handler to display images in UI thread
Handler handler = new Handler();

public ImageLoader(Context context) {
fileCache = new FileCache(context);
executorService = Executors.newFixedThreadPool(5);
}

final int stub_id = R.drawable.temp;

public void DisplayImage(String url, ImageView imageView) {
imageViews.put(imageView, url);
Bitmap bitmap = memoryCache.get(url);
if (bitmap != null)
imageView.setImageBitmap(bitmap);
else {
queuePhoto(url, imageView);
imageView.setImageResource(stub_id);
}
}

private void queuePhoto(String url, ImageView imageView) {
PhotoToLoad p = new PhotoToLoad(url, imageView);
executorService.submit(new PhotosLoader(p));
}

private Bitmap getBitmap(String url) {
File f = fileCache.getFile(url);

Bitmap b = decodeFile(f);
if (b != null)
return b;

// Download Images from the Internet
try {
Bitmap bitmap = null;
URL imageUrl = new URL(url);
HttpURLConnection conn = (HttpURLConnection) imageUrl
.openConnection();
conn.setConnectTimeout(30000);
conn.setReadTimeout(30000);
conn.setInstanceFollowRedirects(true);
InputStream is = conn.getInputStream();
OutputStream os = new FileOutputStream(f);
Utils.CopyStream(is, os);
os.close();
conn.disconnect();
bitmap = decodeFile(f);
return bitmap;
} catch (Throwable ex) {
ex.printStackTrace();
if (ex instanceof OutOfMemoryError)
memoryCache.clear();
return null;
}
}

// Decodes image and scales it to reduce memory consumption
private Bitmap decodeFile(File f) {
try {
// Decode image size
BitmapFactory.Options o = new BitmapFactory.Options();
o.inJustDecodeBounds = true;
FileInputStream stream1 = new FileInputStream(f);
BitmapFactory.decodeStream(stream1, null, o);
stream1.close();

// Find the correct scale value. It should be the power of 2.
// Recommended Size 512
final int REQUIRED_SIZE = 70;
int width_tmp = o.outWidth, height_tmp = o.outHeight;
int scale = 2;
while (true) {
if (width_tmp / 2 < REQUIRED_SIZE
|| height_tmp / 2 < REQUIRED_SIZE)
break;
width_tmp /= 4;
height_tmp /= 4;
scale *= 4;
}

// Decode with inSampleSize
BitmapFactory.Options o2 = new BitmapFactory.Options();
o2.inSampleSize = scale;
FileInputStream stream2 = new FileInputStream(f);
Bitmap bitmap = BitmapFactory.decodeStream(stream2, null, o2);
stream2.close();
return bitmap;
} catch (FileNotFoundException e) {
} catch (IOException e) {
e.printStackTrace();
}
return null;
}

// Task for the queue
private class PhotoToLoad {
public String url;
public ImageView imageView;

public PhotoToLoad(String u, ImageView i) {
url = u;
imageView = i;
}
}

class PhotosLoader implements Runnable {
PhotoToLoad photoToLoad;

PhotosLoader(PhotoToLoad photoToLoad) {
this.photoToLoad = photoToLoad;
}

@Override
public void run() {
try {
if (imageViewReused(photoToLoad))
return;
Bitmap bmp = getBitmap(photoToLoad.url);
memoryCache.put(photoToLoad.url, bmp);
if (imageViewReused(photoToLoad))
return;
BitmapDisplayer bd = new BitmapDisplayer(bmp, photoToLoad);
handler.post(bd);
} catch (Throwable th) {
th.printStackTrace();
}
}
}

boolean imageViewReused(PhotoToLoad photoToLoad) {
String tag = imageViews.get(photoToLoad.imageView);
if (tag == null || !tag.equals(photoToLoad.url))
return true;
return false;
}

// Used to display bitmap in the UI thread
class BitmapDisplayer implements Runnable {
Bitmap bitmap;
PhotoToLoad photoToLoad;

public BitmapDisplayer(Bitmap b, PhotoToLoad p) {
bitmap = b;
photoToLoad = p;
}

public void run() {
if (imageViewReused(photoToLoad))
return;
if (bitmap != null)
photoToLoad.imageView.setImageBitmap(bitmap);
else
photoToLoad.imageView.setImageResource(stub_id);
}
}

public void clearCache() {
memoryCache.clear();
fileCache.clear();
}

}

最佳答案

试试这个..

JSONArray json_query_flag = c.getJSONArray("flag");
for(int i=0;i<json_query_flag.length();i++)
{
Log.v("URL"+json_query_flag.getString(i));
}

编辑

ImageLoader imageLoader=new ImageLoader(activity.this);

并将图像设置为

imageLoader.DisplayImage(URL, imageview);

这里imageview是那个imageview的名字,URl是那个字符串Url

 Bitmap bitmap = null;
try {
imageURL = new URL(utl2);
}

catch (MalformedURLException e) {
e.printStackTrace();
}

try {
HttpURLConnection connection = (HttpURLConnection) imageURL
.openConnection();
connection.setDoInput(true);
connection.connect();
InputStream inputStream = connection.getInputStream();

bitmap = BitmapFactory.decodeStream(inputStream);
image_view.setImageBitmap(bitmap);
} catch (IOException e) {
e.printStackTrace();
}

关于android - 如何解析和显示 json 数组中的 url 内容?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20718390/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com