java - 我必须为一个程序编写两个方法，当用户提示宽度和高度时计算矩形的面积和周长？

Question

import java.util.Scanner;

public class InteractiveRectangle
{
    public static void main(String[] args)
    {

         int height = readPositiveInteger("Enter the height");

         int width = readPositiveInteger("Enter the width");

         printRectangleDetails(height, width);
    }

    /**
     * Read in an integer and return its value
     * @param the prompt to be shown to the user
     */
     public static int readInteger(String prompt)
    {

        Scanner scan = new Scanner(System.in);

        System.out.println(prompt);

        while (!scan.hasNextInt()) // while non-integers are present...
        {
            scan.next(); //...read and discard input, then prompt again

            System.out.println ("Bad input. Enter an integer");
         }

        int firstInteger = scan.nextInt();

        return firstInteger;

    }

    /**
     * Read in an integer greater than 0 and return its value
     * @ param the prompt to be shown to the user
     */
     public static int readPositiveInteger(String prompt)
    {
        int input = 0;

        Scanner scan = new Scanner(System.in);

        boolean first = false;

        while (!scan.hasNextInt())
        {
            int quantity = scan.nextInt();

            if (quantity > 0)
        {
            first = true;

            quantity = scan.nextInt();

        } 
            else if (quantity <= 0)
        {
            System.out.println("Bad input. Enter a positive integer.");
        }

        }
         return input;
   }

     /**
     * Returns the area of a rectangle
     * @param height the height of the rectangle
     * @param width the width of the rectangle
     */

      public static int area (int height, int width)
     {
        return height * width;
      }

     /**
      * Returns the perimeter of a retangle
      * @param height the height of the rectangle
      * @param width the width of the rectangle
      */
      public static int perimeter (int height, int width)
      {
         return (height * 2) + (width * 2);
      }

    /**
     * Prints the area, the perimeter, the length and the width 
     * @param heigth the height of the rectangle
     * @param width the width of the rectangle
     */
     public static void printRectangleDetails (int height, int width)
    {
        System.out.println("The height is " + height);

        System.out.println("The width is " + width);

        System.out.println("The area is " + area(height, width));

        System.out.println("The perimeter is " + perimeter(height, width));
    }
}

到目前为止，这是我的程序，但我在 readPositiveInteger 方法方面遇到了一些问题，我还必须编写一个方法，询问用户是否想要另一个矩形，如果需要，则输入“y”，如果需要，则输入“n”不使用 while 循环。谢谢您

Answer 1

使用do-while让您的代码至少执行一次然后询问用户是否想再次计算结果

char ch = 'y';
do{
int height = readPositiveInteger("Enter the height");
int width = readPositiveInteger("Enter the width");
printRectangleDetails(height, width);
System.out.print("Do you want to calculate other rectangle (y/n) ? : ");
Scanner reader = new Scanner(System.in);
char = reader.next().charAt(0);
}while(ch=='y' || ch=='Y');