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c++解密来自游戏客户端的消息

转载 作者:行者123 更新时间:2023-11-30 03:08:41 25 4
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我制作了一个接受游戏连接的套接字,在游戏中你应该输入用户名和密码,我可以接收它 bt,就像嗯加密的字母和数字(”VeDbç)3¥ثuo_‰°""Fِمض)

我的问题是去哪里看,这样我才能理解如何处理这个问题,有没有一个啧啧。或提示或其他我可以处理的事情,以便我可以找到我正在寻找的东西!?

谢谢。


unsigned char* Key3;
unsigned char* Key4;
unsigned char Low;
unsigned char High;

const unsigned char Key1[] =
{
0x9D, 0x90, 0x83, 0x8A, 0xD1, 0x8C, 0xE7, 0xF6, 0x25, 0x28, 0xEB, 0x82, 0x99, 0x64, 0x8F, 0x2E,
0x2D, 0x40, 0xD3, 0xFA, 0xE1, 0xBC, 0xB7, 0xE6, 0xB5, 0xD8, 0x3B, 0xF2, 0xA9, 0x94, 0x5F, 0x1E,
0xBD, 0xF0, 0x23, 0x6A, 0xF1, 0xEC, 0x87, 0xD6, 0x45, 0x88, 0x8B, 0x62, 0xB9, 0xC4, 0x2F, 0x0E,
0x4D, 0xA0, 0x73, 0xDA, 0x01, 0x1C, 0x57, 0xC6, 0xD5, 0x38, 0xDB, 0xD2, 0xC9, 0xF4, 0xFF, 0xFE,
0xDD, 0x50, 0xC3, 0x4A, 0x11, 0x4C, 0x27, 0xB6, 0x65, 0xE8, 0x2B, 0x42, 0xD9, 0x24, 0xCF, 0xEE,
0x6D, 0x00, 0x13, 0xBA, 0x21, 0x7C, 0xF7, 0xA6, 0xF5, 0x98, 0x7B, 0xB2, 0xE9, 0x54, 0x9F, 0xDE,
0xFD, 0xB0, 0x63, 0x2A, 0x31, 0xAC, 0xC7, 0x96, 0x85, 0x48, 0xCB, 0x22, 0xF9, 0x84, 0x6F, 0xCE,
0x8D, 0x60, 0xB3, 0x9A, 0x41, 0xDC, 0x97, 0x86, 0x15, 0xF8, 0x1B, 0x92, 0x09, 0xB4, 0x3F, 0xBE,
0x1D, 0x10, 0x03, 0x0A, 0x51, 0x0C, 0x67, 0x76, 0xA5, 0xA8, 0x6B, 0x02, 0x19, 0xE4, 0x0F, 0xAE,
0xAD, 0xC0, 0x53, 0x7A, 0x61, 0x3C, 0x37, 0x66, 0x35, 0x58, 0xBB, 0x72, 0x29, 0x14, 0xDF, 0x9E,
0x3D, 0x70, 0xA3, 0xEA, 0x71, 0x6C, 0x07, 0x56, 0xC5, 0x08, 0x0B, 0xE2, 0x39, 0x44, 0xAF, 0x8E,
0xCD, 0x20, 0xF3, 0x5A, 0x81, 0x9C, 0xD7, 0x46, 0x55, 0xB8, 0x5B, 0x52, 0x49, 0x74, 0x7F, 0x7E,
0x5D, 0xD0, 0x43, 0xCA, 0x91, 0xCC, 0xA7, 0x36, 0xE5, 0x68, 0xAB, 0xC2, 0x59, 0xA4, 0x4F, 0x6E,
0xED, 0x80, 0x93, 0x3A, 0xA1, 0xFC, 0x77, 0x26, 0x75, 0x18, 0xFB, 0x32, 0x69, 0xD4, 0x1F, 0x5E,
0x7D, 0x30, 0xE3, 0xAA, 0xB1, 0x2C, 0x47, 0x16, 0x05, 0xC8, 0x4B, 0xA2, 0x79, 0x04, 0xEF, 0x4E,
0x0D, 0xE0, 0x33, 0x1A, 0xC1, 0x5C, 0x17, 0x06, 0x95, 0x78, 0x9B, 0x12, 0x89, 0x34, 0xBF, 0x3E
};
const unsigned char Key2[] =
{
0x62, 0x4F, 0xE8, 0x15, 0xDE, 0xEB, 0x04, 0x91, 0x1A, 0xC7, 0xE0, 0x4D, 0x16, 0xE3, 0x7C, 0x49,
0xD2, 0x3F, 0xD8, 0x85, 0x4E, 0xDB, 0xF4, 0x01, 0x8A, 0xB7, 0xD0, 0xBD, 0x86, 0xD3, 0x6C, 0xB9,
0x42, 0x2F, 0xC8, 0xF5, 0xBE, 0xCB, 0xE4, 0x71, 0xFA, 0xA7, 0xC0, 0x2D, 0xF6, 0xC3, 0x5C, 0x29,
0xB2, 0x1F, 0xB8, 0x65, 0x2E, 0xBB, 0xD4, 0xE1, 0x6A, 0x97, 0xB0, 0x9D, 0x66, 0xB3, 0x4C, 0x99,
0x22, 0x0F, 0xA8, 0xD5, 0x9E, 0xAB, 0xC4, 0x51, 0xDA, 0x87, 0xA0, 0x0D, 0xD6, 0xA3, 0x3C, 0x09,
0x92, 0xFF, 0x98, 0x45, 0x0E, 0x9B, 0xB4, 0xC1, 0x4A, 0x77, 0x90, 0x7D, 0x46, 0x93, 0x2C, 0x79,
0x02, 0xEF, 0x88, 0xB5, 0x7E, 0x8B, 0xA4, 0x31, 0xBA, 0x67, 0x80, 0xED, 0xB6, 0x83, 0x1C, 0xE9,
0x72, 0xDF, 0x78, 0x25, 0xEE, 0x7B, 0x94, 0xA1, 0x2A, 0x57, 0x70, 0x5D, 0x26, 0x73, 0x0C, 0x59,
0xE2, 0xCF, 0x68, 0x95, 0x5E, 0x6B, 0x84, 0x11, 0x9A, 0x47, 0x60, 0xCD, 0x96, 0x63, 0xFC, 0xC9,
0x52, 0xBF, 0x58, 0x05, 0xCE, 0x5B, 0x74, 0x81, 0x0A, 0x37, 0x50, 0x3D, 0x06, 0x53, 0xEC, 0x39,
0xC2, 0xAF, 0x48, 0x75, 0x3E, 0x4B, 0x64, 0xF1, 0x7A, 0x27, 0x40, 0xAD, 0x76, 0x43, 0xDC, 0xA9,
0x32, 0x9F, 0x38, 0xE5, 0xAE, 0x3B, 0x54, 0x61, 0xEA, 0x17, 0x30, 0x1D, 0xE6, 0x33, 0xCC, 0x19,
0xA2, 0x8F, 0x28, 0x55, 0x1E, 0x2B, 0x44, 0xD1, 0x5A, 0x07, 0x20, 0x8D, 0x56, 0x23, 0xBC, 0x89,
0x12, 0x7F, 0x18, 0xC5, 0x8E, 0x1B, 0x34, 0x41, 0xCA, 0xF7, 0x10, 0xFD, 0xC6, 0x13, 0xAC, 0xF9,
0x82, 0x6F, 0x08, 0x35, 0xFE, 0x0B, 0x24, 0xB1, 0x3A, 0xE7, 0x00, 0x6D, 0x36, 0x03, 0x9C, 0x69,
0xF2, 0x5F, 0xF8, 0xA5, 0x6E, 0xFB, 0x14, 0x21, 0xAA, 0xD7, 0xF0, 0xDD, 0xA6, 0xF3, 0x8C, 0xD9
};

// Decrypt Function
void CAuthCryptography::Decrypt(void* in, void* out, int Length)
{
unsigned char* pIn = (unsigned char*)in;
unsigned char* pOut = (unsigned char*)out;
for (int i = 0; i < Length; i++)
{
pOut[i] = (unsigned char)(pIn[i] ^ 0xAB);
pOut[i] = (unsigned char)((pOut[i] << 4) | (pOut[i] >> 4));
if (UsingAlternate)
{
pOut[i] = (unsigned char)(Key4[In.High] ^ pOut[i]);
pOut[i] = (unsigned char)(Key3[In.Low] ^ pOut[i]);
}
else
{
pOut[i] = (unsigned char)(Key2[In.High] ^ pOut[i]);
pOut[i] = (unsigned char)(Key1[In.Low] ^ pOut[i]);
}
In.Counter++;
}
}

我得到了这段代码并且它可以工作但是有人可以向我解释它是如何工作的因为我不明白它吗?!或者如果有一个啧啧。我会读书什么的

最佳答案

我建议您使用 WireShark、tcpdump 等工具来查看 TCP 流,只是为了确保您没有编写 tcp 数据读取代码。更一般地说,如果你得到这样的数据,那么只有发送方会知道为什么,你要么问他们,要么看看他们制作的其他接收程序如何处理这些数据(即调试另一个客户端,找出它对那些烂摊子做了什么)。

关于c++解密来自游戏客户端的消息,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/4756247/

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