java - 数组中等于 N 的连续数的所有可能的和

Question

我试图从数组中的连续元素中找到所有可能的和，这些元素的总和达到特定的数字。例如:-

a[] = {4,7,2,1,3,8,5}; and N = 13,
Output = {4,7,2},{7,2,1,3},{8,5} 

这是我的代码 -

 int low = 0;
        int high = 0;
        int sum = a[0];
        while(high < a.length) {
            if(sum < 13) {
                high++;

                if(high < a.length) {
                    sum+= a[high];

                }
            } else if(sum > 13) {
                sum-=a[low];
                low++;

            }
            if(sum == 13) {
                for(int i=low;i<=high;i++) {
                    System.out.println(a[i]);
                }
                System.out.println("new ");
                low++;
                high++;
                sum = 0;
                //return;
            }
        }

但输出仅返回一组 {4,7,2} 。我无法打印其他套装。谁能帮我解决这个问题

Answer 1

找到第一个序列后，您没有正确重置变量:

        if(sum == 13) {
            for(int i=low;i<=high;i++) {
                System.out.println(a[i]);
            }
            System.out.println("new ");
            low++;
            high++; // change to high = low; // since you want your loop to test 
                    // sequences that start at the new (post incremented) low
            sum = 0; // change to sum = a[low]; // since the initial sum is the value of
                     // the first element in the new sequence
        }