java - 将对象转换为字符串时出错

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在我的 Controller 类中，我使用 ObjectMapper 读取 JSON 数据，然后将这些值存储在 MyPojo 类中，现在我想打印 POJO 对象中的内容。如果我做system.out.println(pojo);它显示一些十六进制值。那么我应该怎么做才能获得您的内容。

这是我的模型类:

package com.ge.health.model;

import java.util.Date;

public class JSONmodel {
    private String message;
    private String data;
    private String datetime;

    public String getDatetime() {
        return datetime;
    }
    public void setDatetime(String datetime) {
        this.datetime = datetime;
    }
    public String getMessage() {
        return message;
    }
    public void setMessage(String message) {
        this.message = message;
    }
    public String getData() {
        return data;
    }
    public void setData(String data) {
        this.data = data;
    }
}

这是我的主类 Controller 类

package com.ge.health.poc.controller;

import java.io.IOException;

import org.springframework.web.bind.annotation.RequestBody;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.ResponseBody;
import org.springframework.web.bind.annotation.RestController;

import com.fasterxml.jackson.core.JsonParseException;
import com.fasterxml.jackson.databind.JsonMappingException;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.ge.health.model.JSONmodel;

@RestController
public class JSONSendController {

    @RequestMapping(value="/messagejson",method= RequestMethod.POST)
    @ResponseBody
    public void helloService(@RequestBody(required = false) String input) throws JsonParseException, JsonMappingException, IOException {            
        ObjectMapper mapper = new ObjectMapper();    
        JSONValidationClass validate=new JSONValidationClass();
        System.out.println("Service Says 123 - " + input);  
        boolean retValue = validate.isValidJSON(input);
        System.out.println("this is the value:"+retValue);
        JSONmodel pojodata = mapper.readValue(input, JSONmodel.class);
        System.out.println(pojodata);
        System.out.println(pojodata.toString());
    }
}

Answer 1

您需要用一些可以告诉您想知道的内容来覆盖 toString():

public String toString() {
        return "message: " + message +
                ",\n data: " + data + 
                ",\n datetime: " + datetime;
}