java - 点击 "delete"按钮后如何删除按钮？

Question

除了删除部分之外，我的程序似乎运行良好。每次我单击“删除”按钮时，它都会自行删除。所以我的问题是，单击“删除”按钮后如何删除所选按钮？这是我的代码片段:

public class DeleteButton extends JFrame implements ActionListener 
{    
  JButton b18a = new JButton("Delete");
  JPanel panel = new JPanel();
  panel.add(b18);

  class ClickListenerTwo implements ActionListener
  {
    public void actionPerformed(ActionEvent e)
    {
         JButton buttonThatWasClicked = (JButton) e.getSource();
         Container parent = buttonThatWasClicked.getParent();
         parent.remove(buttonThatWasClicked);
         parent.revalidate();
         parent.repaint();
    }
  }
}
ActionListener b18aClicked = new ClickListenerTwo();
b18a.addActionListener(b18aClicked); 

P.S - 我正在谈论的这个选定按钮是在运行时创建的，因此如果可能的话，我也想在运行时删除它。谢谢!

Answer 1

因此，假设您需要先单击“其他”按钮，则可以使用实例字段来维护对“最后”单击的按钮的引用，然后在单击删除按钮时使用该引用

例如...

import java.awt.BorderLayout;
import java.awt.EventQueue;
import java.awt.GridLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.UIManager;
import javax.swing.UnsupportedLookAndFeelException;

public class Test {

    public static void main(String[] args) {
        new Test();
    }

    public Test() {
        EventQueue.invokeLater(new Runnable() {
            @Override
            public void run() {
                try {
                    UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
                } catch (ClassNotFoundException | InstantiationException | IllegalAccessException | UnsupportedLookAndFeelException ex) {
                    ex.printStackTrace();
                }

                JFrame frame = new JFrame("Testing");
                frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
                frame.add(new TestPane());
                frame.pack();
                frame.setLocationRelativeTo(null);
                frame.setVisible(true);
            }
        });
    }

    public class TestPane extends JPanel {

        private JButton lastButton;

        public TestPane() {
            JPanel grid = new JPanel(new GridLayout(8, 8));
            for (int index = 0; index < 8 * 8; index++) {
                JButton btn = new JButton(Integer.toString(index + 1));
                btn.addActionListener(new ActionListener() {
                    @Override
                    public void actionPerformed(ActionEvent e) {
                        lastButton = btn;
                    }
                });
                grid.add(btn);
            }

            JButton delete = new JButton("Delete");
            delete.addActionListener(new ActionListener() {
                @Override
                public void actionPerformed(ActionEvent e) {
                    if (lastButton != null) {
                        lastButton.getParent().remove(lastButton);
                        grid.revalidate();
                        grid.repaint();
                    }
                    lastButton = null;
                }
            });

            setLayout(new BorderLayout());
            add(grid);
            add(delete, BorderLayout.SOUTH);
        }

    }

}

就个人而言，JToggleButton 会提供更好的用户体验