C++数组输出地址？

Question

我第一次发帖较早，几乎可以完成这项作业。该程序没有给出错误，但我得到了不希望的结果。输出似乎是输出数组地址而不是我输入的数据。或者至少我认为这是基于我非常非常有限的知识。谁能帮助指导我如何解决这个问题？我整天都在为此工作，在这个时候，我想我已经准备好认输了。非常感谢任何建议，谢谢!

// Amanda 
// SoccerPlayer.cpp : main project file.
// October 6, 2012
/* a. Design a SoccerPlayer class that includes three integer fields: a player's jersey     number,
number of goals, and number of assists. Overload extraction and insertion operators for    the class.
b. Include an operation>() function for the class. One SoccerPlayer is considered greater
than another if the sum of goals plus assists is greater.
c. Create an array of 11 SoccerPlayers, then use the > operator to find the player who  has the
greatest goals plus assists.*/

#include "stdafx.h"
#include<conio.h>
#include<iostream>
#include<string>
using namespace std;



class SoccerPlayer
{
    friend std::ostream& operator<<(std::ostream&, const SoccerPlayer&);
    friend istream& operator>>(istream&, SoccerPlayer&);
private:
    int jerseyNum;
    int numGoals;
    int numAssists;
public:
    SoccerPlayer(int, int, int);
    int score;
    int operator>(SoccerPlayer&);
    void DisplayStar();

};

SoccerPlayer::SoccerPlayer(int jersey = 0, int goal = 0, int assist = 0)
{
    jerseyNum = jersey;
    numGoals = goal;
    numAssists = assist;
} 

void SoccerPlayer::DisplayStar()
{
    cout<<"Player Number: "<< jerseyNum <<endl;
    cout<<"Goals Scored:  "<< numGoals <<endl;
    cout<<"Assists Made:  "<< numAssists <<endl;
} 

std::ostream& operator<<(std::ostream& player,  const SoccerPlayer& aPlayer)
{
    player << "Jersey #" << aPlayer.jerseyNum <<
        " Number of Goals " << aPlayer.numGoals << 
        " Number of Assists " << aPlayer.numAssists;
    return player;
}

std::istream& operator>>(std::istream& inPlayer, SoccerPlayer& aPlayer)
{

    cout << "Please enter the jersey number: ";
    inPlayer >> aPlayer.jerseyNum;
    cout << "Please enter the number of goals: ";
    inPlayer >> aPlayer.numGoals;
    cout << "Please enter the number of assists: ";
    inPlayer >> aPlayer.numAssists;

    aPlayer.score=(aPlayer.numGoals) + (aPlayer.numAssists);



    return inPlayer;
}

int SoccerPlayer::operator>(SoccerPlayer& aPlayer)
{

    int total = 0;
    if (score > aPlayer.score)
        total = 1;
    return total;


}

int main()
{
const int sz = 11;
int x;

SoccerPlayer aPlayer[sz];

for(x = 0; x < sz; ++x)
cin >> aPlayer[x];

{
 double max = aPlayer[x].score; 
 for(int i = 1; i<sz; ++i)
 {
     if(aPlayer[i] > aPlayer[x])
     {
         max=aPlayer[i].score;
     }

  }
 cout << max << endl;
 cout << aPlayer[x];
}
    _getch();
    return 0;
}

Answer 1

看起来好像你打算在这里循环，但它的格式不正确:

for(x = 0; x < sz; ++x)
cin >> aPlayer[x];

{
 double max = aPlayer[x].score; 
 for(int i = 1; i<sz; ++i)
 {
     if(aPlayer[i] > aPlayer[x])
     {
         max=aPlayer[i].score;
     }

  }
 cout << max << endl;
 cout << aPlayer[x];
}

你的意思是(我认为)double max ... 应该在循环内，但是 cin >> ... 行在之后 for 语句，在 大括号之外。所以迭代只适用于 cin >> ... 语句；完成后，控制将转到 double max = aPlayer[x].score;，但是 x(for(...) 遗留下来的)等于 sz，所以 aPlayer[x] 在数组之外，在无人区。

将 cin >> ... 放在括号内。