java - 内部包含尖括号的正则表达式 XML 标签

Question

我需要一个正则表达式，它将给我一个 XML 标签，例如<ABC/>或<ABC></ABC>

所以，如果我使用<(.)+?> ，它会给我<ABC>或<ABC>或</ABC> 。这很好。

现在，问题是:

我有一个 XML 作为

<VALUE ABC="10000" PQR="12422700" ADJ="" PROD_TYPE="COCOG EFI LWL P&amp;C >1Y-5Y" SRC="BASE" DATA="data" ACTION="INSERT" ID="100000" GRC_PROD=""/>

在这里，如果您看到 PROD_TYPE="COCOG EFI LWL P&C >1Y-5Y"属性值中有一个大于符号。

所以，正则表达式返回我

<VALUE ABC="10000" PQR="12422700" ADJ="" PROD_TYPE="COCOG EFI LWL P&amp;C >

而不是完整

<VALUE ABC="10000" PQR="12422700" ADJ="" PROD_TYPE="COCOG EFI LWL P&amp;C >1Y-5Y" SRC="BASE" DATA="data" ACTION="INSERT" ID="100000" GRC_PROD=""/>

我需要一些正则表达式，它不会考虑作为值一部分的小于和大于符号，即用双引号引起来。

Answer 1

你可以试试这个:

(?i)<[a-z][\w:-]+(?: [a-z][\w:-]+="[^"]*")*/?>

解释如下:

(?i)         # Match the remainder of the regex with the options: case insensitive (i)
<            # Match the character “<” literally
[a-z]        # Match a single character in the range between “a” and “z”
[\\w:-]       # Match a single character present in the list below
                # A word character (letters, digits, and underscores)
                # The character “:”
                # The character “-”
   +            # Between one and unlimited times, as many times as possible, giving back as needed (greedy)
(?:          # Match the regular expression below
   \\            # Match the character “ ” literally
   [a-z]        # Match a single character in the range between “a” and “z”
   [\\w:-]       # Match a single character present in the list below
                   # A word character (letters, digits, and underscores)
                   # The character “:”
                   # The character “-”
      +            # Between one and unlimited times, as many times as possible, giving back as needed (greedy)
   =\"           # Match the characters “=\"” literally
   [^\"]         # Match any character that is NOT a “\"”
      *            # Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
   \"            # Match the character “\"” literally
)*           # Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
/            # Match the character “/” literally
   ?            # Between zero and one times, as many times as possible, giving back as needed (greedy)
>            # Match the character “>” literally

如果您喜欢包含 open、close 或 self-close 标签，请尝试下面的 RegEx :

(?i)(?:<([a-z][\w:-]+)(?: [a-z][\w:-]+="[^"]*")*>.+?</\1>|<([a-z][\w:-]+)(?: [a-z][\w:-]+="[^"]*")*/>)

实现相同功能的 java 代码片段:

try {
    boolean foundMatch = subjectString.matches("(?i)(?:<([a-z][\\w:-]+)(?: [a-z][\\w:-]+=\"[^\"]*\")*>.+?</\\1>|<([a-z][\\w:-]+)(?: [a-z][\\w:-]+=\"[^\"]*\")*/>)");
} catch (PatternSyntaxException ex) {
    // Syntax error in the regular expression
}

希望这有帮助...