android - 检索 json 数据

Question

我正在开发一个需要解析 jsonarray 的应用程序。我在 base64 中有我的 json 值，我需要解码字符串以使用解码字符串检索数据。这是我的代码:

 private class DecodeData extends AsyncTask<String, Void, String> {

    @SuppressWarnings("unchecked")
    @Override
    protected String doInBackground(String... params) {
        // TODO Auto-generated method stub
        String response = params[0];
        String keys = "";
        String value = "";
        String b64Value = "";
        LinkedHashMap<String, String> map = new LinkedHashMap<String, String>();
        try {
            JSONArray array = new JSONArray(response);
            for (int i = 0; i < array.length(); i++) {
            Iterator<String> it = array.getJSONObject(i).keys();
                while (it.hasNext()) {
                    keys = (String)it.next();
                    value = (String)array.getJSONObject(i).get(keys);
                    b64Value = Base64.DecodeStrToStr(value);                        

                    Log.i("ASYNC TASK VALUE", b64Value);
                    map.put(keys, b64Value);
                }
            }
        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        return map.toString();
    }

我只得到第一个 JSONObject，我需要得到所有具有所有值的 JSONObject。我不能使用 getString(name) 因为我的 json 可以有其他键。我做错了什么，为什么我只得到第一个 JSONObject 而不是其他对象？

json 类型:

[
{
"value": "ZG1WdVpISmxaR2tnTWpVZ1lYWnlhV3c4WW5JZ0x6NEtSMVZaUVU1QklFRk1UQ0JUVkVGUw==",
"date_create": "MjAxNC0wNC0yNSAwMDowMDowMA==",
"picture": "aHR0cDovL3dzLmFwcHMtcGFuZWwubmV0L2RhdGEvcGFsYWNpby8yNWF2cmlsLmpwZw==",
"link": "",
"title": "MjVhdnJpbA==",
"media": "",
"id_news": "MTA5NjI0",
"id_reference": "",
"type": "",
"id_categorie": "",
"date_event": "MjAxNC0wNC0yNSAwMDowMDowMA==",
"chapo": "",
"auteur": "",
"value_out": "dmVuZHJlZGkgMjUgYXZyaWxHVVlBTkEgQUxMIFNUQVI="
},
{
"value": "YzJGdFpXUnBJREkySUdGMmNtbHNQR0p5SUM4K0NrMUJVbFpKVGlCaGJtUWdSbEpKUlU1RVV3PT0=",
"date_create": "MjAxNC0wNC0yNiAwMDowMDowMA==",
"picture": "aHR0cDovL3dzLmFwcHMtcGFuZWwubmV0L2RhdGEvcGFsYWNpby8yNmF2cmlsMi5qcGc=",
"link": "",
"title": "MjZhdnJpbA==",
"media": "",
"id_news": "MTA5NjMx",
"id_reference": "",
"type": "",
"id_categorie": "",
"date_event": "MjAxNC0wNC0yNiAwMDowMDowMA==",
"chapo": "",
"auteur": "",
"value_out": "c2FtZWRpIDI2IGF2cmlsTUFSVklOIGFuZCBGUklFTkRT"
},

这是我的代码得到的结果:

RESPONSE :{date_create=MjAxNC0wNS0yNSAwMDowMDowMA==, link=, date_event=MjAxNC0wNS0yNSAwMDowMDowMA==, type=, value_out=ZGltYW5jaGUgMjUgbWFpRE9MQSBNSVpJSyBlbiBjb25jZXJ0, picture=aHR0cDovL3dzLmFwcHMtcGFuZWwubmV0L2RhdGEvcGFsYWNpby8yNW1haS5qcGc=, title=MjUgbWFp, id_reference=, chapo=, value=WkdsdFlXNWphR1VnTWpVZ2JXRnBQR0p5SUM4K0NqeGljaUF2UGdwRVQweEJJRTFKV2tsTElHVnVJR052Ym1ObGNuUT0=, id_news=MTA5NjM0, media=, auteur=, id_categorie=}

有人知道我该怎么做吗？

谢谢

Answer 1

问题:

您将所有结果放在同一个 map 中。 JSONArray 中的每个对象都会删除之前对象的值，因为键是相同的。

最后，每个键只能得到一个值。

解决方案:

数组中的每个 JSON 对象需要一个映射。例如，您可以使用 map 列表(或数组)。这是一些代码:

ArrayList<HashMap<String, String>> decodedArray = new ArrayList<>();
JSONArray array = new JSONArray(response);
for (int i = 0; i < array.length(); i++) {
    HashMap<String, String> map = new HashMap<>();
    Iterator<String> it = array.getJSONObject(i).keys();
    while (it.hasNext()) {
        keys = (String) it.next();
        value = (String) array.getJSONObject(i).get(keys);
        b64Value = Base64.DecodeStrToStr(value);                        
        Log.i("ASYNC TASK VALUE", b64Value);
        map.put(keys, b64Value);
    }
    decodedArray.add(map);
}