java - 无法获得完整的 HttpResponse

Question

我将我的代码放在 AsyncTask 中，在 OnPostExecution 中，Dialog 中的结果与 Logcat 中记录的结果不同。Logcat里的不全，Dialog里的全

这是我的代码:

    private class DownloadTask extends AsyncTask<String, Void, String>{     
    @Override
    protected String doInBackground(String... params) {
        // TODO Auto-generated method stub          
        String url =params[0];
        String data = "";
        try{
            HttpClient httpClient = new DefaultHttpClient();
            HttpContext localContext = new BasicHttpContext();
            HttpPost httpPost = new HttpPost(url);
            HttpResponse httpResponse = httpClient.execute(httpPost,localContext);
            int status = httpResponse.getStatusLine().getStatusCode();
            if(status == 200){ //Receive OK
                data = EntityUtils.toString(httpResponse.getEntity());
            }
        }catch(Exception e){
            Log.e("HTTP", "ERROR");
        }
        return data;
    }

    @Override
    protected void onPostExecute(String result) {
        // TODO Auto-generated method stub
        super.onPostExecute(result);    
            AlertDialog.Builder builder = new Builder(MainActivity.this);
            builder.setMessage(result);
            builder.setPositiveButton("OK", null);
            builder.create().show();
            Log.d("Response", result);
    }       

在 onCreate() 方法中，我执行了 DownloadTask:

String url = "https://maps.googleapis.com/maps/api/directions/json?origin=10.9052136,106.6928473&destination=10.736465,106.710779&sensor=false&units=metric&mode=driving";

DownloadTask downloadTask = new DownloadTask();
downloadTask.execute(url);

我想接收完整的结果以解析为 JSON

Answer 1

尝试:

InputStream in = httpResponse.getEntity().getContent();

并查看 Read/convert an InputStream to a String如果您真的需要它作为String。

将其维护为 InputStream 并将that 传递给 JSON 解析器会更好。