c++ - 设置 uchar 的位

Question

我正在尝试设置一个 uchar 如下:

uchar num = 0;
    //0
    num <<= 1;
    //1
    num |=1;
    num <<=1;
    //0
    num <<=1;
    //1
    num |=1;
    num <<=1;
    //0
    num <<=1;
    //1
    num |=1;
    num <<=1;
    //0
    num <<= 1;
    //0
    num <<=1;
    //should be 01010100 = 84
    std::cout << " num is " << num << " int " << (unsigned int) num << std::endl;

应该以二进制 8 位序列 01010100 结束，十进制为 84。但是，当我打印输出时，我得到的是 num is ® int 168

我做错了什么？

谢谢

Answer 1

最后一类太多了。 84 乘以 2 得到 168