gpt4 book ai didi

java - 为什么过滤器链从未被调用?

转载 作者:行者123 更新时间:2023-11-30 02:43:36 24 4
gpt4 key购买 nike

我目前正在开发一个可从应用程序池访问的网络应用程序。基本上,这个池提供了一组指向每个应用程序的链接,传递一个标识先前登录用户的 key 。

相关应用程序应该使用给定的 token (可能来自任何请求 URL)授权用户,将用户存储到 spring 安全上下文中并处理 Controller 。碰巧 Spring Security 过滤器没有被调用,并且 Controller 返回到 500 而不是 403

我尝试了一些东西,最终得到了一个自定义入口点转发到自定义UsernamePasswordAuthenticationFilter来检索用户,然后自定义AuthenticationProvider应该授权检索到的用户,但是我很确定这不是最好的方法。

SecurityConfig.java

@Configuration
@EnableWebSecurity
@EnableGlobalMethodSecurity(securedEnabled = true)
public class SecurityConfig extends WebSecurityConfigurerAdapter {

@Autowired
private SwgenAuthFilter swgenAuthFilter;

@Override
protected void configure(HttpSecurity http) throws Exception {
http.httpBasic()
.and()
.authorizeRequests()
.anyRequest()
.authenticated()
.and()
.exceptionHandling()
.accessDeniedPage("/403")
.authenticationEntryPoint(new SwgenEntryPoint())
.and()
.addFilter(swgenAuthFilter);
}

@Override
public void configure(WebSecurity web) throws Exception {
web.ignoring().antMatchers("/static/**");
}

@Bean
@Override
public AuthenticationManager authenticationManagerBean() throws Exception {
return new ProviderManager(Arrays.asList(new SwgenAuthProvider()));
}

}

SwgenEntryPoint.java

public class SwgenEntryPoint implements AuthenticationEntryPoint {

@Override
public void commence(HttpServletRequest request, HttpServletResponse response, AuthenticationException authException)
throws IOException, ServletException {
RequestDispatcher dispatcher = request.getRequestDispatcher("/login");

dispatcher.forward(request, response);

return;
}

}

SwgenAuthFilter.java

@Component
public class SwgenAuthFilter extends UsernamePasswordAuthenticationFilter {

@Autowired
private SecurityProvider securityProvider;

@Override
public Authentication attemptAuthentication(HttpServletRequest request, HttpServletResponse response) throws AuthenticationException {
try {
User user = securityProvider.getUser(request, response);
return new UsernamePasswordAuthenticationToken(user, null);
} catch (Exception e) {
throw new AuthenticationServiceException("Eccezione scatenata durante l'autenticazione", e);
}
}

@Override
@Autowired
public void setAuthenticationManager(AuthenticationManager authenticationManager) {
super.setAuthenticationManager(authenticationManager);
}

}

HomeController.java

@Controller
public class HomeController {

static final private Logger logger = Logger.getLogger(HomeController.class);

@Secured({Role.ADMIN, Role.REGIONE})
@RequestMapping(value = "/home")
public String home(Model model, HttpServletRequest request) {
// get user from SpringContextHolder
User utente = Utils.getUser();

if(utente != null) {
logger.info("User correctly authenticated")
}

return "home";
}
}

堆栈跟踪

2016-12-01 12::03:07.343 DEBUG [org.springframework.security.access.intercept.aopalliance.MethodSecurityInterceptor] Secure object: ReflectiveMethodInvocation: public java.lang.String it.regioneveneto.sanita.progettobase.controller.HomeController.home(org.springframework.ui.Model,javax.servlet.http.HttpServletRequest); target is of class [it.regioneveneto.sanita.progettobase.controller.HomeController]; Attributes: [ROLE_MRA_ADMIN, ROLE_MRA_REGIONE, ROLE_MRA_ULSS]
dic 01, 2016 12:03:07 PM org.apache.catalina.core.StandardWrapperValve invoke
GRAVE: Servlet.service() for servlet [dispatcher] in context with path [/mra_auac] threw exception [Request processing failed; nested exception is org.springframework.security.authentication.AuthenticationCredentialsNotFoundException: An Authentication object was not found in the SecurityContext] with root cause
org.springframework.security.authentication.AuthenticationCredentialsNotFoundException: An Authentication object was not found in the SecurityContext
at org.springframework.security.access.intercept.AbstractSecurityInterceptor.credentialsNotFound(AbstractSecurityInterceptor.java:379)
at org.springframework.security.access.intercept.AbstractSecurityInterceptor.beforeInvocation(AbstractSecurityInterceptor.java:223)
at org.springframework.security.access.intercept.aopalliance.MethodSecurityInterceptor.invoke(MethodSecurityInterceptor.java:65)
at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:179)
at org.springframework.aop.framework.CglibAopProxy$DynamicAdvisedInterceptor.intercept(CglibAopProxy.java:655)
at it.regioneveneto.sanita.progettobase.controller.HomeController$$EnhancerBySpringCGLIB$$8c44d861.home(<generated>)
...

Spring mvc: 4.3.4.RELEASE

Spring security: 4.2.0.RELEASE

编辑:

web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">

<display-name>mra_auac</display-name>
<description>MRA-AuAc</description>

<context-param>
<param-name>contextClass</param-name>
<param-value>
org.springframework.web.context.support.AnnotationConfigWebApplicationContext
</param-value>
</context-param>

<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>it.regioneveneto.sanita.progettobase.configuration.AppConfig</param-value>
</context-param>

<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextClass</param-name>
<param-value>org.springframework.web.context.support.AnnotationConfigWebApplicationContext</param-value>
</init-param>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>
it.regioneveneto.sanita.progettobase.configuration.HibernateConfig,
it.regioneveneto.sanita.progettobase.configuration.security.SecurityConfig
</param-value>
</init-param>
<multipart-config>
<max-file-size>20971520</max-file-size><!--20MB -->
<max-request-size>20971520</max-request-size><!--20MB -->
<file-size-threshold>0</file-size-threshold>
</multipart-config>
</servlet>

<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<error-page>
<error-code>404</error-code>
<location>/404.htm</location>
</error-page>
<error-page>
<error-code>500</error-code>
<location>/500.htm</location>
</error-page>

<session-config>
<session-timeout>60</session-timeout>
</session-config>

</web-app>

最佳答案

正如shazin指出的那样,您的web.xml缺少对springSecurityFilterChain的引用。您可以按照 Spring Documentation 中报告的方式进行操作。使用xml格式:

<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>
org.springframework.web.filter.DelegatingFilterProxy
</filter-class>
</filter>

<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
<dispatcher>ERROR</dispatcher>
<dispatcher>REQUEST</dispatcher>
</filter-mapping>

在项目中包含一个扩展 AbstractSecurityWebApplicationInitializer 的类,如下所示:

public class SecurityWebApplicationInitializer 
extends AbstractSecurityWebApplicationInitializer {}

然后,如果您想从 web.xml 中删除一些代码,您可以通过替换轻松实现

<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>
it.regioneveneto.sanita.progettobase.configuration.HibernateConfig,
it.regioneveneto.sanita.progettobase.configuration.security.SecurityConfig
</param-value>
</init-param>

用以下方式注释类AppConfig:

@Import({ SecurityConfig.class, HibernateConfig.class }) //remember to import them

关于java - 为什么过滤器链从未被调用?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40909181/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com