c++ - 通过连接另一个 char* 来初始化 const char*

Question

我要重构:

const char* arr = 
  "The "
  "quick "
  "brown";

变成类似的东西:

const char* quick = "quick ";
const char* arr = 
  "The "
  quick
  "brown";

因为字符串“quick”被用在很多其他地方。理想情况下，我需要能够只使用 const 原始类型来做到这一点，所以没有字符串。执行此操作的最佳方法是什么？

Answer 1

以答案的形式编译评论:

1. 使用宏。

   #define QUICK "quick "
   
   char const* arr = "The " QUICK "brown";
   

2. 使用std:string。

   std::string quick = "quick ";
   std::string arr = std::string("The ") + quick + "brown";
   

工作代码:

#include <iostream>
#include <string>

#define QUICK "quick "

void test1()
{
   char const* arr = "The " QUICK "brown";
   std::cout << arr << std::endl;
}

void test2()
{
   std::string quick = "quick ";
   std::string arr = std::string("The ") + quick + "brown";
   std::cout << arr << std::endl;
}

int main()
{
   test1();
   test2();
}

输出:

The quick brown
The quick brown