c++ - 将一个对象的所有QT信号动态映射到一个插槽

Question

我想将一个 QObject 的所有信号连接到某个插槽。

插槽看起来像这样:

void SignalIntercepter::signalFired()
{
    std::cout << "Signal is fired!" << std::endl;
}

以下代码是 QObject 将被传递到的地方:

void SignalIntercepter::handleObject(QObject* object)
{
    const QMetaObject *me = object->metaObject();
    int methodCount = me->methodCount();
    for(int i = 0; i < methodCount; i++)
    {
        QMetaMethod method = me->method(i);
        if(method.methodType() == QMetaMethod::Signal)
        {
            // How do I connect this signal to the slot?
            // QObject::connect(object, ..., ..., ...);
        }
    }
}

Answer 1

看看

const char * QMetaMethod::signature() const

那么你应该可以像这样使用它

QObject::connect(object, method->signature(), this, SLOT(signalFired()));

您可能需要在 method->signature() 调用之前添加 "2" 因为 SIGNAL(a) makro 已定义 SIGNAL(a) "2"#a 如前所述Is it possible to see definition of Q_SIGNALS, Q_SLOT, SLOT(), SIGNAL() macros? (Qt)