gpt4 book ai didi

c++ - boost::asio + std::future - 关闭套接字后访问冲突

转载 作者:行者123 更新时间:2023-11-30 02:35:36 26 4
gpt4 key购买 nike

我正在编写一个简单的 tcp 客户端来发送和接收单行文本。异步操作由 std::future 处理,以促进超时阻塞查询。不幸的是,我的测试应用程序在破坏服务器对象时因访问冲突而崩溃。这是我的代码:

TCP客户端.hpp

#ifndef __TCPCLIENT_H__
#define __TCPCLIENT_H__

#include <boost/asio.hpp>
#include <boost/asio/use_future.hpp>
#include <memory>
#include <vector>
#include <future>
#include <thread>
#include <chrono>
#include <iostream>
#include <iterator>

using namespace boost::asio;

class TCPClient {
public:
TCPClient();
~TCPClient();

void connect(const std::string& address, const std::string& port);
void disconnect();

std::string sendMessage(const std::string& msg);
private:
boost::asio::io_service ioservice;
boost::asio::io_service::work work;
std::thread t;

std::unique_ptr<boost::asio::ip::tcp::socket> socket;
};

inline TCPClient::TCPClient() : ioservice(), work(ioservice) {
t = std::thread([&]() {
try {
ioservice.run();
}
catch (const boost::system::system_error& e) {
std::cerr << e.what() << std::endl;
}
});
}

inline TCPClient::~TCPClient() {
disconnect();
ioservice.stop();
if (t.joinable()) t.join();
}

inline void TCPClient::connect(const std::string& address, const std::string& port) {
socket.reset(new ip::tcp::socket(ioservice));

ip::tcp::resolver::query query(address, port);
std::future<ip::tcp::resolver::iterator> conn_result = async_connect(*socket, ip::tcp::resolver(ioservice).resolve(query), use_future);

if (conn_result.wait_for(std::chrono::seconds(6)) != std::future_status::timeout) {
conn_result.get(); // throws boost::system::system_error if the operation fails
}
else {
//socket->close();
// throw timeout_error("Timeout");
throw std::exception("timeout");
}
}

inline void TCPClient::disconnect() {
if (socket) {
try {
socket->shutdown(ip::tcp::socket::shutdown_both);
std::cout << "socket points to " << std::addressof(*socket) << std::endl;
socket->close();
}
catch (const boost::system::system_error& e) {
// ignore
std::cerr << "ignored error " << e.what() << std::endl;
}
}
}

inline std::string TCPClient::sendMessage(const std::string& msg) {
auto time_over = std::chrono::system_clock::now() + std::chrono::seconds(4);

/*
// Doesn't affect the error
std::future<size_t> write_fut = boost::asio::async_write(*socket, boost::asio::buffer(msg), boost::asio::use_future);

try {
write_fut.get();
}
catch (const boost::system::system_error& e) {
std::cerr << e.what() << std::endl;
}
*/
boost::asio::streambuf response;

std::future<std::size_t> read_fut = boost::asio::async_read_until(*socket, response, '\n', boost::asio::use_future);
if (read_fut.wait_until(time_over) != std::future_status::timeout) {
std::cout << "read " << read_fut.get() << " bytes" << std::endl;
return std::string(std::istreambuf_iterator<char>(&response), std::istreambuf_iterator<char>());
}
else {
std::cout << "socket points to " << std::addressof(*socket) << std::endl;
throw std::exception("timeout");
}
}
#endif

主要.cpp

#include <iostream>

#include "TCPClient.hpp"

int main(int argc, char* argv[]) {
TCPClient client;
try {
client.connect("localhost", "27015");
std::cout << "Response: " << client.sendMessage("Hello!") << std::endl;
}
catch (const boost::system::system_error& e) {
std::cerr << e.what() << std::endl;
}
catch (const std::exception& e) {
std::cerr << e.what() << std::endl;
}
system("pause");
return 0;
}

输出如预期的那样“超时”(测试服务器故意不发送数据),但是 ioservice.run()TCPClient 中关闭套接字后立即崩溃(访问冲突): :断开连接()。我在这里做一些内存管理不善吗?

编译器是 MSVC 12.0.31101.00 Update 4 (Visual Studio 2013)

最佳答案

recvmsg 正在接收缓冲区 (streambuf),该缓冲区在 TCPClient::sendMessage 中抛出异常后被释放(第 105 行,结束范围)。

您忘记取消第 97 行开始的异步操作 (async_read_until)。修复它:

else {
socket->cancel(); // ADDED
std::cout << "socket points to " << std::addressof(*socket) << std::endl;
throw std::runtime_error("timeout");
}

甚至,只是

    socket.reset(); // ADDED

其他超时路径也是如此。

关于c++ - boost::asio + std::future - 关闭套接字后访问冲突,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33442464/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com