java - 将字符串(使用正则表达式)转换为可用对象

Question

对于一个项目，我们正在使用 telnet 服务器，我们从中接收数据。从 telnet 连接读取一行后，我得到以下字符串:

原始字符串:

SVR GAME MOVE {PLAYER: "PLAYER", MOVE: "1", DETAILS: ""}

我正在尝试将其转换为我可以轻松使用的输出，而不会发生太多可利用性。所需的格式是轻松获取(玩家)或获取。我尝试将 regex 与 json 结合使用，请参阅下面的代码:

String line = currentLine;
line = line.replaceAll("(SVR GAME MOVE )", ""); //remove SVR GAME MATCH
line = line.replaceAll("(\"|-|\\s)", "");//remove quotations and - and spaces (=\s)
line = line.replaceAll("(\\w+)", "\"$1\""); //add quotations to every word
JSONParser parser = new JSONParser();
try {
       JSONObject json = (JSONObject) parser.parse(line);
       //@todo bug when details is empty causes
       //@todo example string: SVR GAME MOVE {PLAYER: "b", MOVE: "1", DETAILS: ""}
       //@todo string that (line) that causes an error when parsing to json {"PLAYER":"b","MOVE":"1","DETAILS":}
       //@todo Unexpected token RIGHT BRACE(}), i think because "details" has no value
       System.out.println(json.get("PLAYER"));
       System.out.println(json.get("MOVE"));
       System.out.println(json.get("DETAILS"));
       int index = Integer.valueOf(json.get("MOVE").toString());
       for(GameView v : views){
          v.serverMove(index);//dummy data is index 1
       }
    } catch (ParseException e) {
        e.printStackTrace();
}

问题是，当详细信息为空时，这会导致意外的标记右括号(})。此外，当玩家使用剥削性名称(例如名称中的引号)时，代码很容易崩溃。

将原始字符串转换为可以轻松获得单独设置(玩家、移动、详细信息)的输出的最佳方法是什么？

Answer 1

这将解析字符串并将变量放入映射中:

    Map<String,String> vars = new HashMap<>();
    String input = "SVR GAME MOVE {PLAYER: \"PLAYER\", MOVE: \"1\", DETAILS: \"\"}";
    Pattern pattern = Pattern.compile("([A-Za-z]+): \"([^\"]*)\"");
    Matcher matcher = pattern.matcher(input);
    while (matcher.find()) {
        vars.put(matcher.group(1), matcher.group(2));
    }