c++ - 我如何优化此代码以这种格式打印？

Question

我想打印这样一个链表:

0       1       2       3       4
12      24      36      85      48

我现在的代码是

void LinkedList::printList()
{
    curr = head; //store head in curr to irerate
    int count = 0; //counter to help uer manipulate list
    while (curr != NULL) //traverse whole list
    {
        cout << count++ <<"\t"; //print index
        curr = curr->next; //move to next 
    }
    curr = head; //make current head again
    cout << endl;//go to next line
    while (curr != NULL) //traverse whole list
    {
        cout << curr->data << "\t"; //print data
        curr = curr->next; //move to next 
    }
    cout << endl;
}

我很确定还有另一种方法可以做到这一点，它更简单、更快捷。我想减少这段代码的冗余。

我正在显示计数器以帮助用户添加或删除号码。

Answer 1

#include <sstream>
void LinkedList::printList(std::ostream& os = std::cout) {
    size_t counter = 0;
    std::ostringstream indx;
    std::ostringstream value;
    for( ListNode *current = head; current != NULL; current = current->next ) {
        indx << counter++ << "\t";
        value << current->data << "\t";
    }
    os << indx.str().c_str() << std::endl << value.str().c_str() << std::endl;
}

• 只遍历一次List
• for 循环而不是 while。
• 速度并不重要，因为您的列表应该很小(除非您有非常非常宽的屏幕或非常小的字体)，因为您希望列表的内容能够整齐地适合输出窗口的 1 行。<