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java - 拖放图像按钮有 onDrag 问题

转载 作者:行者123 更新时间:2023-11-30 02:29:08 24 4
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我正在开发一个 Android 应用程序,用户可以在其中购买建筑物,这些建筑物是实现拖放 API 的图像按钮。我的问题是,当用户购买两座建筑物时,比如 colonyHutOne 和 colonyHutTwo,在 onDrag 中保存的 x 和 y 坐标存在问题。在我的 onDrag 中,我在 onDragListener 中传递了哪个建筑物编号,所以我知道我在 onDrag 类中处理的建筑物。这样我就可以将坐标保存到适当的建筑物中。问题是,无论我将什么建筑物编号传递给 onDrag,最近创建的建筑物都是采用坐标的建筑物。在 onDrag 中,即使它是第一个被拖动的建筑物(即第一个建筑物),它每次都会收到第二个建筑物。我不知道这是否与传递给 onDrag 的上下文有关,或者是否因为在进行拖动之前声明了 onDragListeners,所以它只采用最后创建的图像按钮。我不知道如何解决这个问题。请帮忙。

下面是设置两个建筑物的拖动监听器的代码:

findViewById(R.id.topHalf).setOnDragListener(new ColonyHutDrag(getApplicationContext(), 1));
findViewById(R.id.bottomHalf).setOnDragListener(new ColonyHutDrag(getApplicationContext(), 1));
FrameLayout.LayoutParams param1 = new FrameLayout.LayoutParams(FrameLayout.LayoutParams.WRAP_CONTENT, FrameLayout.LayoutParams.WRAP_CONTENT);
newColonyHutFrame.addView(newColonyHutOne, param1);

findViewById(R.id.topHalf).setOnDragListener(new ColonyHutDrag(getApplicationContext(), 2));
findViewById(R.id.bottomHalf).setOnDragListener(new ColonyHutDrag(getApplicationContext(), 2));
FrameLayout.LayoutParams param1 = new FrameLayout.LayoutParams(FrameLayout.LayoutParams.WRAP_CONTENT, FrameLayout.LayoutParams.WRAP_CONTENT);
newColonyHutFrame.addView(newColonyHutTwo, param1);

这是 onDrag 类:

public class ColonyHutDrag implements OnDragListener
{
SharedPreferences prefs;
Context passedContext;
Database data;
int buildingNum = 0;

public ColonyHutDrag(Context applicationContext, int num)
{
passedContext = applicationContext;
buildingNum = num;
}//end constructor

@Override
public boolean onDrag(View v, DragEvent event)
{
float x = 0, y = 0;
switch(event.getAction())
{
case DragEvent.ACTION_DRAG_STARTED:
//drag has started
break;

case DragEvent.ACTION_DRAG_ENTERED:
//being dragged
break;

case DragEvent.ACTION_DRAG_EXITED:
//stop drag
break;

case DragEvent.ACTION_DRAG_LOCATION:
//find drag location
break;

case DragEvent.ACTION_DROP:
if (v == v.findViewById(R.id.bottomHalf))
{
//find position where dropped
x = event.getX();
y = event.getY();

//save the coordinates that the building was dropped at
data = new Database(passedContext);
data.open();
if (buildingNum == 1)
{
data.colonyHutOneXEntry(x);
data.colonyHutOneYEntry(y);
Toast.makeText(passedContext, "Going in1 -> x: " + x + " y: " + y, Toast.LENGTH_SHORT).show();
}//end if
else if (buildingNum == 2)
{
data.colonyHutTwoXEntry(x);
data.colonyHutTwoYEntry(y);
Toast.makeText(passedContext, "Going in2 -> x: " + x + " y: " + y, Toast.LENGTH_SHORT).show();
}//end else if

data.close();

//use this to fix building loadup glitch
View view = (View) event.getLocalState();
ViewGroup group = (ViewGroup) view.getParent();
group.removeView(view);
FrameLayout contain = (FrameLayout) v;
contain.addView(view);
view.setX(x - (view.getWidth()/2));
view.setY(y - (view.getHeight()/2));
view.setVisibility(View.VISIBLE);
}//end if
else
{
View view = (View) event.getLocalState();
view.setVisibility(View.VISIBLE);
}//end else
break;

default:
break;
}//end switch
return true;
}//end onDrag function
}//end ColonyHutOneDrag class

这是拖放的 onTouchlistener:

public class BuildingsClick implements OnTouchListener 
{
@Override
public boolean onTouch(View v, MotionEvent event)
{
ClipData.Item item = new ClipData.Item((CharSequence)v.getTag());

String[] mimeTypes = { ClipDescription.MIMETYPE_TEXT_PLAIN };
ClipData data = new ClipData(v.getTag().toString(), mimeTypes, item);
DragShadowBuilder shadowBuilder = new View.DragShadowBuilder(v);

v.startDrag(data, shadowBuilder, v, 0);
v.setVisibility(View.INVISIBLE);

return false;
}//end onTouch function

}//end BuildingsClick class

非常感谢任何帮助。我不知道如何解决这个问题。几乎就像是既然处理了第二栋,那第一栋就不能再引用了。谢谢大家。

编辑:

BuildingsClick 类中的代码

//find which building is being dragged
if (v.getTag() == "NewColonyHutOne")
{
ColonyHutDrag.setType(ColonyHutOneDrag.getType());
}//end if
else if (v.getTag() == "NewColonyHutTwo")
{
ColonyHutDrag.setType(ColonyHutTwoDrag.getType());
}//end if

ColonyHutOneDrag 类的代码:

public class ColonyHutOneDrag extends ColonyHut
{

@Override
public int getType()
{
return 1;
}//end getType

}//end ColonyHutOneDrag

ColonyHutTwoDrag 类的代码与第一个相同,但返回 2。

这是 ColonyHutDrag 中的 getType:

public void setType(int type)
{
buildingNum = type;
}//end setType

最佳答案

您错误地再次分配了 OnDragListener

你不能

findViewById(R.id.topHalf).setOnDragListener(new ColonyHutDrag(getApplicationContext(), 1));
findViewById(R.id.bottomHalf).setOnDragListener(new ColonyHutDrag(getApplicationContext(), 1));
FrameLayout.LayoutParams param1 = new FrameLayout.LayoutParams(FrameLayout.LayoutParams.WRAP_CONTENT, FrameLayout.LayoutParams.WRAP_CONTENT);

然后

findViewById(R.id.topHalf).setOnDragListener(new ColonyHutDrag(getApplicationContext(), 2));
findViewById(R.id.bottomHalf).setOnDragListener(new ColonyHutDrag(getApplicationContext(), 2));
FrameLayout.LayoutParams param1 = new FrameLayout.LayoutParams(FrameLayout.LayoutParams.WRAP_CONTENT, FrameLayout.LayoutParams.WRAP_CONTENT);

原因是因为您的第二次调用覆盖了您的第一次调用,并且您从不监听要拖动的小屋类型 1,因为您在构造函数中传递了正在监听的小屋。

解决这个问题的方法是改变你对监听器的分配,像这样:

findViewById(R.id.topHalf).setOnDragListener(new ColonyHutDrag(getApplicationContext()));
findViewById(R.id.bottomHalf).setOnDragListener(new ColonyHutDrag(getApplicationContext());
FrameLayout.LayoutParams param1 = new FrameLayout.LayoutParams(FrameLayout.LayoutParams.WRAP_CONTENT, FrameLayout.LayoutParams.WRAP_CONTENT);

我们将创建一个抽象类ColonyHut,并定义public int getType();

同时去掉 ColonyHutListener 的构造函数,我们不需要它。然后你将创建一个名为 ColonyHutOne 的类,如果你还没有的话。使用该类,您将要扩展 ColonyHut,并像这样定义 getType():

public int getType()
{
return 1;
}

然后我们将在您的 ColonyHutDrag 类中定义一个名为 setType() 的函数,如下所示:

public void setType(int type)
{
buildingNum = type;
}

之后,您将希望将 ColonyHutOne 作为 ColonyHut,就像这样 ColonyHut currentlySelectedHut = view.getHutFromView()在您的 onTouchListener 中,并在 v.startDrag() 之前调用 colonyHutDrag.setType(currentlySelectedHut.getType()) 它应该可以工作。对 ColonyHutTwo 做同样的事情,除了显然你应该让 getType() 返回 2。

我将保留定义 view.getHutFromView(),并使 colonyHutDrag 在您的 BuildingsClick 类中可见。毕竟一切都不可能是免费的:-)。

关于java - 拖放图像按钮有 onDrag 问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27515974/

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