c++ - 如何找到动态分配数组的不同行的大小？

Question

我有以下代码:

int *exceptions[7];
int a[] = {1, 4, 11, 13};
int b[] = {5, 6, 11, 12, 14, 15};
int c[] = {2, 12, 14, 15};
int d[] = {1, 4, 7, 9, 10, 15};
int e[] = {1, 3, 4, 5, 7, 9};
int f[] = {1, 2, 3, 7, 13};
int g[] = {0, 1, 7, 12};

exceptions[0] = a;
exceptions[1] = b;
exceptions[2] = c;
exceptions[3] = d;
exceptions[4] = e;
exceptions[5] = f;
exceptions[6] = g;

exception[0] 和 exception[1] 的大小应分别为 4 和 6。

这是我的代码:

short size = sizeof(exceptions[1]) / sizeof(exceptions[1][0]);

但我得到的每一行都是 2。我该如何解决这个问题？

Answer 1

 short size = sizeof(exceptions[1]) / sizeof(exceptions[1][0]);

实际上和

一样

 short size = sizeof(int*) / sizeof(int);

在 64 位平台上，这很可能产生 2 .

---

How can I solve this problem?

使用一些 C++ 标准容器，如 std::vector<std::vector<int>>相反:

std::vector<std::vector<int>> exceptions {
    {1, 4, 11, 13},
    {5, 6, 11, 12, 14, 15},
    {2, 12, 14, 15},
    {1, 4, 7, 9, 10, 15},
    {1, 3, 4, 5, 7, 9},
    {1, 2, 3, 7, 13},
    {0, 1, 7, 12},
}

你的声明将变成:

 short size = exceptions[0].size();
 size = exceptions[1].size();

(无论需要什么)