java - Java中点击Button1和Button2会按照顺序变成多种颜色

Question

当我点击button1时，button2会变成红色，当我第二次点击button1时，button2会变成黄色。当button2为蓝色时，点击button1后，button2会变回红色。我的代码不正确，但我希望编写与此类似的代码。

private void jButton1ActionPerformed(java.awt.event.ActionEvent evt) {                                         
    
    String[] colorsArray = {"red","yellow","green","blue"};
    
    for(int i = 0; i < 4; i++)
        jButton2.setBackground(Color.colorsArray[i]);
}

代码错误:

cannot find symbol

symbol: variable colorsArray

location: class Color

Answer 1

编辑:您的颜色数组与此方法位于同一类中，而不是位于名为 Color 的类中，如代码 Color.colorsArray 所示。代码已修复

您不需要for循环。您需要存储 BT2 的当前状态，并在到达终点时循环。

这样你就可以从currentColor == 0开始。当您单击按钮时，您设置红色BG，即设置currentColor == 1。下次，您将其设置为黄色。当currentColor == 4时，您将其设置为0以重新开始。

// put this outside method, as class member
private final String[] colorsArray = {"red","yellow","green","blue"};
private int currentColor = 0;

private void jButton1ActionPerformed(java.awt.event.ActionEvent evt) {                                         
    if (currentColor == colorsArray.length) {
        currentColor = 0;
    }

    jButton2.setBackground(colorsArray[currentColor]);

    currentColor = currentColor + 1;
}