java - 使用 JAXB 解码在下面的代码中给出 null 吗？

Question

无法弄清楚为什么下面的代码中的编码对象为空。您能指出我缺少什么吗？

还有一个问题:

setStaffList(List<Staff> staffList)中是否需要运行for循环在职员类。我对这一点有点困惑。

xml:

<?xml version="1.0"?>
<company>
    <staff id="1001">
        <firstname>YW</firstname>
        <lastname>mook kim</lastname>
        <nickname>mkyong</nickname>
        <salary>100000</salary>
    </staff>
    <staff id="2001">
        <firstname>low</firstname>
        <lastname>yin fong</lastname>
        <nickname>fong fong</nickname>
        <salary>200000</salary>
    </staff>
</company>

解码代码:

public class XmlToList {
    public static void main(String[] args) {
        File xmlFile = new File("D:/CoreJavaPractice/XMLCode/src/staff.xml");
        JAXBContext jaxbContext;
        Company comp;
        try {
            jaxbContext = JAXBContext.newInstance(Company.class);
            comp = (Company) jaxbContext.createUnmarshaller().unmarshal(xmlFile);
            System.out.println(comp + "; " + xmlFile);

            List<Staff> staffList = comp.getStaffList();
            System.out.println(staffList);

            for (Staff s : staffList) {
                System.out.println(s.getFirstname());
            }
        } catch (JAXBException e) {
            e.printStackTrace();
        }    
    }

}

公司类别:

@XmlRootElement(name = "company")
public class Company {
    List<Staff> staffList;

    public Company() {
    }

    public Company(List<Staff> staffList) {
        this.staffList = staffList;

    }

    public List<Staff> getStaffList() {
        return staffList;
    }

    public void setStaffList(List<Staff> staffList) {
        /*
         * for (Staff s : staffList) { this.staffList.add(s); }
         */
        this.staffList = staffList;
    }
}

员工等级:

@XmlRootElement(name = "staff")
public class Staff {

    Integer id;
    String firstname;
    String lastname;
    String nickname;
    String salary;

    public Staff() {
    }

    public Staff(Integer id, String firstname, String lastname, String nickname, String salary) {
        super();
        this.id = id;
        this.firstname = firstname;
        this.lastname = lastname;
        this.nickname = nickname;
        this.salary = salary;
    }

    public Integer getId() {
        return id;
    }

    @XmlAttribute
    public void setId(Integer id) {
        this.id = id;
    }

    public String getFirstname() {
        return firstname;
    }

    @XmlElement
    public void setFirstname(String firstname) {
        this.firstname = firstname;
    }

    public String getLastname() {
        return lastname;
    }

    @XmlElement
    public void setLasttname(String lasttname) {
        this.lastname = lasttname;
    }

    public String getNickname() {
        return nickname;
    }

    @XmlElement
    public void setNickname(String nickName) {
        this.nickname = nickName;
    }

    public String getSalary() {
        return salary;
    }

    @XmlElement
    public void setSalary(String salary) {
        this.salary = salary;
    }

}

Answer 1

建议您显式设置XmlAccessorType和XmlElement，这样您的Company类将是:

@XmlRootElement(name = "company")
@XmlAccessorType(XmlAccessType.PROPERTY)
public class Company {
    private List<Staff> staffList;

    public Company() {
    }

    public Company(List<Staff> staffList) {
        this.staffList = staffList;

    }

    public List<Staff> getStaffList() {
        return staffList;
    }

    @XmlElement(name = "staff")
    public void setStaffList(List<Staff> staffList) {
        this.staffList = staffList;
    }
}