android - 如何从回收者 View 将结果返回到 fragment

Question

我有一个带有 fragment B 的 Activity B，我使用 startActivityForResult 从 Activity A 打开它。在我的 fragment B 中，我有一个回收器 GridView 。在 GridView 中，我有用于显示动画 gif 的 WebView 网格。

我的 fragment B代码

public static class GiphyFragment extends Fragment {

private RecyclerView mRecyclerView;
private GiphyTestAdapter mAdapter;
private RecyclerView.LayoutManager mLayoutManager;

public GiphyFragment() {
}

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
                         Bundle savedInstanceState) {
    View rootView = inflater.inflate(R.layout.fragment_giphy_test, container, false);

    mRecyclerView = (RecyclerView) rootView.findViewById(R.id.giphy_recycler_view);
    mRecyclerView.setHasFixedSize(true);

    // use a grid layout manager
    mLayoutManager = new GridLayoutManager(getActivity(),2);
    mRecyclerView.setLayoutManager(mLayoutManager);

    // specify an adapter
    ArrayList<Giphy> giphyDataSet = new ArrayList<Giphy>();
    mAdapter = new GiphyTestAdapter(getActivity(),giphyDataSet);
    mRecyclerView.setAdapter(mAdapter);

    //run async task to fetch list of giphys
    ...
    ...

    return rootView;
}
}

Giphy测试适配器

public class GiphyTestAdapter extends RecyclerView.Adapter<GiphyTestAdapter.ViewHolder> {

private final String LOG_TAG = getClass().getSimpleName();
private ArrayList<Giphy> mDataset;
private Context mContext;

public class ViewHolder extends RecyclerView.ViewHolder{
    public WebView giphyView;
    public TextView textView;

    public ViewHolder(View v) {
        super(v);
        giphyView = (WebView) v.findViewById(R.id.giphy_view);
        textView = (TextView) v.findViewById(R.id.giphy_url);
        this.giphyView.setWebViewClient(new WebViewClient(){
            @Override
            public boolean shouldOverrideUrlLoading(WebView view, String url){
                Toast toast = Toast.makeText(mContext, textView.getText(), Toast.LENGTH_SHORT);
                toast.show();
                //Here I want to return result to fragment so that it can give it to activity A
                return true;
            }
        });
    }
}

public void add(int position, Giphy giphyObj) {
    mDataset.add(giphyObj);
    notifyItemInserted(position);
}

public GiphyTestAdapter(Context context, ArrayList<Giphy> myDataset) {
    mContext = context;
    mDataset = myDataset;
}

// Create new views (invoked by the layout manager)
@Override
public GiphyTestAdapter.ViewHolder onCreateViewHolder(ViewGroup parent,
                                               int viewType) {
    View v = LayoutInflater.from(parent.getContext()).inflate(R.layout.fragment_giphy_item_list, parent, false);
    ViewHolder vh = new ViewHolder(v);
    return vh;
}

// Replace the contents of a view (invoked by the layout manager)
@Override
public void onBindViewHolder(ViewHolder holder, int position) {
    final Giphy giphy = mDataset.get(position);
    holder.giphyView.loadUrl(giphy.getUrl());
    holder.textView.setText(giphy.getUrl());
}

@Override
public int getItemCount() {
    return mDataset.size();
}
}

目标 我想将结果返回给 Activity A。

通常我会在 fragment B 中创建一个 Intent ，使用 put extra 添加所需的结果并调用 finish。

在上面的代码中，我在 shouldOverrideUrlLoading 方法中返回了数据。如何给它 fragment B 以便它可以创建 Intent 并返回？

Answer 1

尝试使用 getActivity().setResult(int responseCode, Intent data) 并在 Activity A 中覆盖 Activity.onActivityResult(int requestCode, int responseCode, Intent data)