java - JOOQ动态条件查询

Question

大家好，我尝试制定一种方法来应用 SelectQuery 条件，但我不知道如何按名称获取字段或按名称获取表，代码示例...

过滤条件的对象是一个数组，如下所示:

[{'field': 'ID', 'condition' : 'in', 'value' : ['f4019bc3-d06b-4673-87e7-75bab23ac85a','c13beeef-2893-4a04-9ebf-ecdc851475bc']}]

查询生成器方法如下所示:

public List<Branch> find(String order, JSONArray filters, Integer limit, Integer pageNumber) {
    SelectQuery<Record6<String,Integer,String,String,String,String>> selectSentence = dsl.select(
            branch.ID.as("id"),
            branch.CODE.as("code"), 
            branch.NAME.as("name"), 
            enterprises.ID.as("enterprise.id"), 
            enterprises.NAME.as("enterprise.name"), 
            enterprises.NIT.as("enterprise.nit"))
            .from(branch)
            .leftOuterJoin(enterprises)
            .on(branch.ENTERPRISE.eq(enterprises.ID)).getQuery();
    if(order != null && order.startsWith("-")) {
            selectSentence.addOrderBy(Tables.BRANCH.field(order.substring(1)).desc());
    }else {
            selectSentence.addOrderBy(Tables.BRANCH.field(order).asc());
    }
    addQueryConditions(filters, selectSentence);
    selectSentence.addLimit(limit);
    selectSentence.addOffset((pageNumber - 1) * limit);
    return selectSentence.fetchInto(Branch.class);
}

addQueryConditions 看起来像:

@SuppressWarnings("unchecked")
private void addQueryConditions(JSONArray filters, SelectQuery<?> query) {
    for (int i = 0, size = filters.length(); i < size; i++){
        JSONObject filter = filters.getJSONObject(i);
        String filterCondition = filter.optString("condition");
        if(Comparator.EQUALS.toSQL().equals(filterCondition)) {
            Field<Object> field = (Field<Object>) query.field(filter.optString("field"));
            Comparator comparator = Comparator.EQUALS;
            query.addConditions(field.compare(comparator, filter.optString("value")));
        }else if(Comparator.GREATER.toSQL().equals(filterCondition)) {
            Field<Object> field = (Field<Object>) query.field(filter.optString("field"));
            Comparator comparator = Comparator.GREATER;
            query.addConditions(field.compare(comparator, filter.optString("value")));
        }else if(Comparator.GREATER_OR_EQUAL.toSQL().equals(filterCondition)) {
            Field<Object> field = (Field<Object>) query.field(filter.optString("field"));
            Comparator comparator = Comparator.GREATER_OR_EQUAL;
            query.addConditions(field.compare(comparator, filter.optString("value")));
        }else if(Comparator.IN.toSQL().equals(filterCondition)) {
            Field<Object> field = (Field<Object>) query.field(filter.optString("field"));
            Comparator comparator = Comparator.IN;
            query.addConditions(field.compare(comparator, filter.optString("value")));
        }else if(Comparator.LESS.toSQL().equals(filterCondition)) {
            Field<Object> field = (Field<Object>) query.field(filter.optString("field"));
            Comparator comparator = Comparator.LESS;
            query.addConditions(field.compare(comparator, filter.optString("value")));
        }else if(Comparator.LESS_OR_EQUAL.toSQL().equals(filterCondition)) {
            Field<Object> field = (Field<Object>) query.field(filter.optString("field"));
            Comparator comparator = Comparator.LESS_OR_EQUAL;
            query.addConditions(field.compare(comparator, filter.optString("value")));
        }else if(Comparator.LIKE.toSQL().equals(filterCondition)) {
            Field<Object> field = (Field<Object>) query.field(filter.optString("field"));
            Comparator comparator = Comparator.LIKE;
            query.addConditions(field.compare(comparator, filter.optString("value")));
        }
    }
}

但该字段总是为空...

我该如何解决这个问题。

Answer 1

各种TableLike.field(String)方法区分大小写。您的 JSON 结构发送此输入

[{'field': 'ID', ...}]

但是您的列已重命名为小写id:

branch.ID.as("id")