php - 安卓/PHP : how to POST/GET JSON data from Android to php

Question

Android/PHP:如何从 Android 到 PHP POST/GET JSON 数据？

目前我被困在将 JSONObject 数据发送到 php 的位置，但是总是在响应中获取 NULL 值。

我想要什么:

我正在以 JSONObject 的形式从 Android 发送“用户名”和“密码”，并希望在 PHP 响应中检索 JSONObject 中的相同数据。

这是我的代码 fragment

Android_file.java

DefaultHttpClient httpClient=new DefaultHttpClient();
        HttpPost httpPost=new HttpPost(register_user);
        JSONObject jsonObject=new JSONObject();
        httpPost.setHeader("Accept", "application/json");
        httpPost.setHeader("Content-type", "application/json");
        try {

            jsonObject.put("username",username.getText().toString());
            jsonObject.put("password",password.getText().toString());
            StringEntity se=new StringEntity("json="+jsonObject.toString());
            //httpPost.addHeader("content-type", "application/x-www-form-urlencoded");
            se.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE,"application/json"));
            httpPost.setEntity(se);
           String req=se.toString();

            HttpResponse response=httpClient.execute(httpPost);


            if(response!=null){
                InputStream is=response.getEntity().getContent();
                BufferedReader bufferedReader=new BufferedReader(new     InputStreamReader(is));
                StringBuilder sb=new StringBuilder();
                String line=null;
                while((line=bufferedReader.readLine())!=null){
                    sb.append(line+"\n");
                }
                this.message=sb.toString();
                //Toast.makeText(getBaseContext(), message, Toast.LENGTH_LONG).show();
            }

        } catch (JSONException e) {
            e.printStackTrace();
        } catch (ClientProtocolException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

登录检查.php

<?php
include('../core/init.php');

 // $contents = file_get_contents('php://input'); 
  // $contents = utf8_encode($contents); 
  if($_POST['json'])
  {
  $data=json_decode(stripslashes($_POST['json']));
  $username=$data['username'];
  $password=$data['password'];
$response=array('username'=>$username,'password'=>$password);
echo json_encode($response);

  }
   else{
   $no_data=array('none'=>'no data received');
echo json_encode($no_data);
   }

    ?>

如果我做错了什么或遗漏了某些要点，请告诉我？提前致谢!

Answer 1

我不知道你的代码到底出了什么问题，但我将你的代码与我的代码进行了比较，后者在不同的应用程序上运行良好，我对你的代码进行了一些更改，希望它能正常工作:

替换部分:

        jsonObject.put("username",username.getText().toString());
        jsonObject.put("password",password.getText().toString());
        StringEntity se=new StringEntity("json="+jsonObject.toString());
        se.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE,"application/json"));
        httpPost.setEntity(se);

与:

        List<NameValuePair> params = new ArrayList<NameValuePair>(); 
        params.add(new BasicNameValuePair("username", username.getText().toString())); 
        params.add(new BasicNameValuePair("password",password.getText().toString())); 
        httpPost.setEntity(new UrlEncodedFormEntity(params)); 

这将是您的网络服务(我认为问题出在这里):

<?php
include('../core/init.php');

 // $contents = file_get_contents('php://input'); 
  // $contents = utf8_encode($contents); 
  if(isset($_POST['username']) && isset($_POST['password']))
  {
      $username=$_POST['username'];
      $password=$_POST['password'];
      $response = array(); 
      $response['username'] = $username; 
      $response['password'] = $password;
      echo json_encode($response);
  }
  else{
       $no_data=array();
       $no_data['none']= 'no data received';
       echo json_encode($no_data);
  }
 ?>

如果它解决了您的问题，请告诉我。