java - 在java中解析JSON(Eclipse)

Question

我有以下 JSON 文本(REST API URL 源)。我如何解析它以获取 ID、姓名、电话、城市等:

{"ID":1,"name":"aaa","phone":["345345345","1244","743"],"city":"asdasd"}
{"ID":2,"name":"bbb","phone":["234234","235","124"]}
{"ID":3,"name":"ccc","phone":["4234","6236","123"],"city":"jhjk"}

谢谢。

编辑:

我运行此代码:

                      String var1 = output;
                       JSONObject obj;
                       try {
                              obj = new JSONObject(var1);
                              String a = obj.getString("name");
                              String b = obj.getString("phone");
                              String c = obj.getString("city");

                              System.out.println("name:" + a);
                              System.out.println("phone:" + b);
                              System.out.println("city:" + c);

我得到了“phone”作为字符串。有人可以添加代码来解析电话线吗？

Answer 1

您可以使用Gson解析 JSON。只需为此创建一个类，Gson 就会为您进行解析。

class MyClass{
    @SerializedName("ID")
    String ID;
    @SerializedName("name")
    String name;
    @SerializedName("phone")
    List<String> phone;
    @SerializedName("city")
    String city;

    public MyClass(String ID, String name, List<String> phone, String city) {
        this.ID = ID;
        this.name = name;
        this.phone = phone;
        this.city = city;
    }

    public String getID() {
        return ID;
    }

    public void setID(String ID) {
        this.ID = ID;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public List<String> getPhone() {
        return phone;
    }

    public void setPhone(List<String> phone) {
        this.phone = phone;
    }

    public String getCity() {
        return city;
    }

    public void setCity(String city) {
        this.city = city;
    }
}

然后在您的主类(class)或 Activity 中:

MyClass myclass= new Gson().fromJSON(jsonString,MyClass.class);
System.out.println(myclass.getID());