c++ - 标准对抛出异常的类型有什么要求？

Question

I thought exceptions imposed a bit more on the thrown type than the standard actually imposes.我想澄清这个困惑。这些类型实际上强加了什么？

Answer 1

C++ ISO 规范，§15.1/3，指出

The type of the throw-expression shall not be an incomplete type, or a pointer or reference to an incomplete type, other than void*, const void*, volatile void*, or const volatile void*. Except for these restrictions and the restrictions on type matching mentioned in 15.3, the operand of throw is treated exactly as a function argument in a call (5.2.2) or the operand of a return statement.

由此看来，您应该能够抛出任何您想要的东西，只要您不抛出您仅转发声明的类型即可。

编辑:正如@Billy ONeal 指出的那样，类型必须是可复制的，这意味着它应该支持复制构造函数。