c++ - 类问题中的静态 int 数组

Question

下面3个代码块分别是main.cpp、static_class_array.cpp、static_class_array.h。我收到以下错误:

static_class_array.cpp||In constructor 'static_array_class::static_array_class()':|
static_class_array.cpp|5|error: cannot convert '<brace-enclosed initializer list>' to 'int' in assignment|
||=== Build finished: 1 errors, 0 warnings ===|

#include "static_class_array.h"

int main()
{
    static_array_class* array_class;

    array_class = new static_array_class();

    delete array_class;

    return 0;
}


#include "static_class_array.h"

static_array_class::static_array_class()
{
    static_array_class::array[3] = {0,1,2};
}
static_array_class::~static_array_class(){}



#ifndef STATIC_CLASS_ARRAY_H
#define STATIC_CLASS_ARRAY_H

class static_array_class
{
    private:

        static int array[3];

    public:

    static_array_class();
    ~static_array_class();
};
#endif

Answer 1

我认为你想要的实现文件是:

    static_array_class::static_array_class()
    {
    }
    static_array_class::~static_array_class(){}

    int static_array_class::array[3] = {0,1,2};

错误信息的解释

"cannot convert 'brace-enclosed initializer list' to 'int' in assignment"

在提交的代码中。

这是因为代码:

static_array_class::array[3] = {0,1,2};

被解释为 {0,1,2} 应该分配给数组中的元素 3。元素 3 是 int 类型，(顺便说一句，没有分配为第四个元素)，所以这就像:

int i = 0;
i = {0,1,2};

因此出现错误消息。