c++ - 了解 C++ 模板

Question

这是我类中的函数声明:

template <typename PointInT, typename PointNT, typename PointOutT>
class WrinklednessEstimation: public FeatureFromNormals<PointInT, PointNT, PointOutT>
{
    ...
    void normalsToSpherical(const PointCloud<PointNT> &input, PointCloud<Normal> &output);
    ...
}

下面是实现的部分:

template <typename PointInT, typename PointNT, typename PointOutT> void
pcl::WrinklednessEstimation<PointInT, PointNT, PointOutT>::normalsToSpherical(const PointCloud<PointNT> &input, PointCloud<Normal> &output)
{
    ...
}

这是编译器的提示:

wrinkledness.cpp: In member function ‘void pcl::WrinklednessEstimation<PointInT, PointNT, pointOutT>::computeFeature(typename pcl::Feature<PointInT, PointOutT>::PointCloudOut&) [with PointInT = pcl::PointWithViewpoint, PointNT = pcl::Normal, PointOutT = pcl::InterestPoint]’:
wrinkledness.cpp:76:   instantiated from here
wrinkledness.cpp:40: error: no matching function for call to ‘pcl::WrinklednessEstimation<pcl::PointWithViewpoint, pcl::Normal, pcl::InterestPoint>::normalsToSpherical(boost::shared_ptr<const pcl::PointCloud<pcl::Normal> >&, boost::shared_ptr<pcl::PointCloud<pcl::Normal> >&)’
wrinkledness.cpp:45: note: candidates are: void pcl::WrinklednessEstimation<PointInT, PointNT, PointOutT>::normalsToSpherical(const pcl::PointCloud<PointOutT>&, pcl::PointCloud<pcl::Normal>&) [with PointInT = pcl::PointWithViewpoint, PointNT = pcl::Normal, PointOutT = pcl::InterestPoint]

我不明白的是，为什么候选人在第一个参数中使用PointOutT而不是PointNT？

谢谢

Answer 1

您在调用函数时使用 boost::shared_ptr 作为参数。尝试使用类似 *my_shared_ptr 的方式调用该函数。