c++ - CPP中原始数据类型的构造函数初始化

Question

在cpp中，我们可以将原始数据类型初始化为

int a(32);

这个构造函数初始化是如何工作的？ C++ 是否将其视为对象？

Answer 1

最好的描述是:

C++03 8.5 初始化器
第 12 和 13 段:

.......
The initialization that occurs in new expressions (5.3.4), static_cast expressions (5.2.9), functional notation type conversions (5.2.3), and base and member initializers (12.6.2) is called
direct-initialization and is equivalent to the form

T x(a);

If T is a scalar type, then a declaration of the form

T x = { a };

is equivalent to

T x = a;

问题中的类型是 int，这是一个标量类型。