java - 获取输入时扫描仪抛出 java.util.NoSuchElementException

Question

下面的代码在函数 aVeryBigSum 中抛出 NoSuchElementException。PS:这是来自hackerrank的任务，所以我只能修改函数中的代码:aVeryBigSum。

该函数接受以下输入:n(数组中要添加的元素数量)以及数组的元素。

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;

public class Solution {

    // Complete the aVeryBigSum function below.
    static long aVeryBigSum(long[] ar) {
        int n, sum = 0;
        Scanner read = new Scanner(System.in);
        n = read.nextInt();
        for(int i = 0; i < n; i++)
            sum += read.nextLong();
        return sum;
    }

    private static final Scanner scanner = new Scanner(System.in);

    public static void main(String[] args) throws IOException {
        BufferedWriter bufferedWriter
                = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));

        int arCount = scanner.nextInt();
        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

        long[] ar = new long[arCount];

        String[] arItems = scanner.nextLine().split(" ");
        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

        for (int i = 0; i < arCount; i++) {
            long arItem = Long.parseLong(arItems[i]);
            ar[i] = arItem;
        }

        long result = aVeryBigSum(ar);

        bufferedWriter.write(String.valueOf(result));
        bufferedWriter.newLine();

        bufferedWriter.close();

        scanner.close();
    }
}

输出:

Answer 1

为什么要在 aVeryBigSum 方法中读取 Scanner 内容？

只需循环 ar 参数并计算总和。

static long aVeryBigSum(long[] ar) {
    long _sum = 0;
    for(int i=0; i < ar.length; i++)
        sum += ar[i];
    return _sum;
}