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c++ - 将数组传递给 C++ 中的函数? [彩票号码]

转载 作者:行者123 更新时间:2023-11-30 02:02:16 25 4
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我正在用 C++ 创建一个彩票游戏。我创建了一个名为 GetLottoPicks 的函数,它要求用户输入 7 个号码。我有另一个名为 GenWinNums 的函数,它生成 7 个随机数。

问题出在 GenWinNums 上,它不断生成 7 次:-858993460

我相信我对参数 int WinningNums[] 进行了输入,但显然没有?

谢谢。

int main()
{
string name;
int choice;
int user_picked[7];
int chosen_lotto[7];

cout << "LITTLETON CITY LOTTO MODEL:" << endl;
cout << "---------------------------" << endl;
cout << " 1) Play Lotto " << endl;
cout << " Q) Quit Program " << endl;
cout << " Please make a selection: ";
cin >> choice;

if (choice == 1)
{
cout << "\n Please enter your name: ";
cin >> name;

getLottoPicks(user_picked);
GenWinNums(chosen_lotto);

for(int i = 0; i < 7; i++)
{
cout << chosen_lotto[i];
}

for(int i = 0; i < 7; i++)
{
cout << user_picked[i];
}
}

else if (choice == 'Q' || 'q')
{
exit(0);
}

else
{
cout << "That is not a valid choice." << endl;
}

system("PAUSE");
return 0;
}

int getLottoPicks(int UserTicket[])
{
const int amount = 7;
UserTicket[amount];
int ticket = UserTicket[amount];

for (int i = 0; i < amount; i++)
{
cout << "\n Please enter number " << i + 1 << ":";
cin >> UserTicket[i];

while (UserTicket[i] < 1 || UserTicket[i] > 40)

{
cout << "Your selection cannot be less than 1 and/or greater than 40. Try Again." << endl;
cin >> UserTicket[i];
}

if(i > 0)
{
for(int check = 0; check < i; check++)
{
while(UserTicket[i] == UserTicket[check])
{
cout << "You cannot use the same lotto number twice. Try again: " << endl;
cin >> UserTicket[i];
}
}
}

}

return ticket;
}

int GenWinNums(int WinningNums[])
{
const int amount = 7;
int numbers[amount];
int ticket = WinningNums[amount];

for(int i = 0; i < amount; i++)
{
numbers[i] = (rand() % 40) + 1;

while(numbers[i] < 1 || numbers[i] > 40)
{
numbers[i] = (rand() % 10) + 1;
}
if(i > 0)
{
for(int check = 0; check < i; check++)
{
while(numbers[i] == numbers[check])
{
numbers[i] = (rand() % 10) + 1;
}
}
}
}
return ticket;
}

最佳答案

只是为了好玩,这里有相当多的修复。我不打算一一列举。基本上:

  • 通过引用传递固定大小的数组,以避免不安全的使用
  • 严格检查输入错误,并在一个循环中完成
  • 一些错误的数组赋值,要么什么都不做,要么阻止结果被调用者看到...
  • 使用 char 作为输入类型(这样 Q 就会匹配)并且更喜欢 aa switch 而不是重复的 ifs
  • 请参阅下面的更典型的 C++ 样式解决方案,包括检查 WIN 或 LOSE

读者练习:为您的 rand() 生成器设置种子,或者中奖非常简单(粘贴之前的中奖彩票:))

演示运行的输出(也显示错误处理):

LITTLETON CITY LOTTO MODEL:
---------------------------
1) Play Lotto
Q) Quit Program
Please make a selection: 1

Please enter your name: me

Please enter number 1:34

Please enter number 2:7

Please enter number 3:16

Please enter number 4:18

Please enter number 5:24

Please enter number 6:24
Duplicate entry 24
Please enter number 6:7
Duplicate entry 7
Please enter number 6:37

Please enter number 7:whoops
Bad input 'whoops' discarded
Please enter number 7:what was the last number again?
Bad input 'what' discarded
Please enter number 7:Bad input 'was' discarded
Please enter number 7:Bad input 'the' discarded
Please enter number 7:Bad input 'last' discarded
Please enter number 7:Bad input 'number' discarded
Please enter number 7:Bad input 'again?' discarded
Please enter number 7:27
User ticket: 7; 16; 18; 24; 27; 34; 37;
Winning ticket: 7; 16; 18; 24; 27; 34; 36;
Result of draw: WINNER

.

#include <string>
#include <iostream>

const size_t amount = 7;

void getLottoPicks(int (&ticket)[amount])
{
for(int i = 0; i < amount; i++)
{
do
{
std::cout << "\n Please enter number " << i + 1 << ":";
if(std::cin >> ticket[i])
{
if(ticket[i] >= 1 && ticket[i] <= 40)
{
bool ok = true;
for(int check = 0; ok && check < i; check++)
{
ok &= (ticket[i] != ticket[check]);
}
if(ok)
{
break;
}
else
{
std::cout << "You cannot use the same lotto number twice. Try again." << std::endl;
}
}
else
{
std::cout << "Your selection cannot be less than 1 and/or greater than 40. Try Again." << std::endl;
}
}
else
{
std::cin.clear();
std::string discard;
std::cin >> discard;
std::cout << "Bad input '" << discard << "' discarded";
}
}
while(true);
}
}

void GenWinNums(int (&winningNumbers)[amount])
{
for(int i = 0; i < amount; i++)
{
winningNumbers[i] = (rand() % 40) + 1;
while(winningNumbers[i] < 1 || winningNumbers[i] > 40)
{
winningNumbers[i] = (rand() % 10) + 1;
}
if(i > 0)
{
for(int check = 0; check < i; check++)
{
while(winningNumbers[i] == winningNumbers[check])
{
winningNumbers[i] = (rand() % 10) + 1;
}
}
}
}
}
int main()
{
std::string name;
char choice;
std::cout << "LITTLETON CITY LOTTO MODEL:" << std::endl;
std::cout << "---------------------------" << std::endl;
std::cout << " 1) Play Lotto " << std::endl;
std::cout << " Q) Quit Program " << std::endl;
std::cout << " Please make a selection: ";
std::cin >> choice;
switch(choice)
{
case '1':
{
std::cout << "\n Please enter your name: ";
std::cin >> name;

int user_picked[amount];
int chosen_lotto[amount];

getLottoPicks(user_picked);
GenWinNums(chosen_lotto);

std::cout << "\n";
for(int i = 0; i < amount; i++)
{
std::cout << user_picked[i] << "; ";
}
std::cout << "\n";
for(int i = 0; i < amount; i++)
{
std::cout << chosen_lotto[i] << "; ";
}
}
case 'Q':
case 'q':
return 0;
default:
std::cout << "\n That is not a valid choice." << std::endl;
}
std::cout << "\n Press enter...";
std::cin >> choice;
}

更典型的C++解决方案

#include <string>
#include <iostream>
#include <algorithm>
#include <iterator>
#include <set>

const size_t amount = 7;

typedef std::set<int> ticket_t;

ticket_t getLottoPicks()
{
ticket_t ticket;
while (ticket.size() < amount)
{
std::cout << "\n Please enter number " << (ticket.size()+1) << ":";

int entry;
if(std::cin >> entry)
{
if(entry >= 1 && entry <= 40)
{
if (ticket.end() != ticket.find(entry))
std::cout << "Duplicate entry " << entry;
else
ticket.insert(entry);
} else
std::cout << "Entry out of range [1..40]: " << entry;

continue;
}

std::cin.clear();
std::string discard;
std::cin >> discard;
std::cout << "Bad input '" << discard << "' discarded";
}
return ticket;
}

ticket_t genWinNums()
{
ticket_t ticket;
while (ticket.size() < amount)
ticket.insert(rand() % 40 + 1);
return ticket;
}

std::ostream& operator<<(std::ostream& os, ticket_t const& t)
{
std::copy(t.begin(), t.end(), std::ostream_iterator<int>(os, "; "));
return os;
}

int main()
{
std::cout << "LITTLETON CITY LOTTO MODEL:" << std::endl;
std::cout << "---------------------------" << std::endl;
std::cout << " 1) Play Lotto " << std::endl;
std::cout << " Q) Quit Program " << std::endl;
std::cout << "Please make a selection: ";
char choice;
std::cin >> choice;

switch(choice)
{
case '1':
{
std::cout << "\n Please enter your name: ";
std::string name;
std::cin >> name;

const ticket_t user = getLottoPicks();
const ticket_t winning = genWinNums();

std::cout << "User ticket: " << user << "\n";
std::cout << "Winning ticket: " << winning << "\n";

// check win?
bool ok = 0 == std::lexicographical_compare(
user.begin(), user.end(),
winning.begin(), winning.end());

std::cout << "Result of draw: " << (ok? "WINNER":"No luck") << "\n";
}
case 'Q': case 'q':
return 0;
default:
std::cout << "\n That is not a valid choice." << std::endl;
}

std::cin.ignore(1<<24,'\n');
std::cout << "\n Press enter...";
std::string dummy;
std::getline(std::cin, dummy);
}

关于c++ - 将数组传递给 C++ 中的函数? [彩票号码],我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13425905/

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