java - 如何获取列表中的所有玩家的最小值

Question

我正在尝试以最少的尝试返回游戏的获胜者。但我不确定如何在平局的情况下执行此操作。

我的获胜者是

try(Scanner scan = new Scanner(new File("result.txt"))){
                while(scan.hasNext()){
                    String[] s = scan.nextLine().split(" ");
                    players.add(new Players(s[0],s[1],Integer.valueOf(s[2])));
                }
                Collections.sort(players, Comparator.comparing((players1) -> players1.getAttempts()));
                //test// System.out.println(players);
                //Collections.sort(players, (a,b)->a.getAttempts().compareTo(b.getAttempts()));


                System.out.println("The winner is: "+ players.get(0).getName() +", with "+players.get(0).getAttempts()+ " attempt(s)!");
            }
            result.close();
}

感谢任何帮助。

Answer 1

首先根据尝试次数对列表进行升序排序

List<Players> sortedList = players.stream().sorted((a,b)->a.getAttempts().compareTo(b.getAttempts())).collect(Collectors.toList())

然后打印所有尝试次数最少的获胜者

sortedList.stream().filter(i->i.getAttempts()==sortedList.stream().findFirst()
  .get().getAttempts()).forEach(winner->System.out.println("The winners are "+winner.getvalues));

或者只是流式传输按升序排序的集合对象

players.filter(i->i.getAttempts()==players.get(0).getAttempts()).forEach(winner->System.out.println("The winners are "+winner.getvalues));