java正则表达式从文本中检索链接

Question

我的输入String为:

String text = "Some content which contains link as <A HREF=\"/relative-path/fruit.cgi?param1=abc&param2=xyz\">URL Label</A> and some text after it";

我想将此文本转换为:

Some content which contains link as http://www.google.com/relative-path/fruit.cgi?param1=abc&param2=xyz&myParam=pqr (URL Label) and some text after it

所以这里:

1) 我想用普通链接替换链接标签。如果标签包含标签，那么它应该放在 URL 后面的大括号中。

2) 如果 URL 是相对的，我想为基本 URL 添加前缀 ( http://www.google.com )。

3) 我想在 URL 中附加一个参数。 (&myParam=pqr)

我在检索包含 URL 和标签的标签并替换它时遇到问题。

我写了这样的内容:

public static void main(String[] args) {
    String text = "String text = "Some content which contains link as <A HREF=\"/relative-path/fruit.cgi?param1=abc&param2=xyz\">URL Label</A> and some text after it";";
    text = text.replaceAll("&lt;", "<");
    text = text.replaceAll("&gt;", ">");
    text = text.replaceAll("&amp;", "&");

    // this is not working
    Pattern p = Pattern.compile("href=\"(.*?)\"");
    Matcher m = p.matcher(text);
    String url = null;
    if (m.find()) {
        url = m.group(1);

    }
}

// helper method to append new query params once I have the url
public static URI appendQueryParams(String uriToUpdate, String queryParamsToAppend) throws URISyntaxException {
    URI oldUri = new URI(uriToUpdate);
    String newQueryParams = oldUri.getQuery();
    if (newQueryParams == null) {
        newQueryParams = queryParamsToAppend;
    } else {
        newQueryParams += "&" + queryParamsToAppend;  
    }
    URI newUri = new URI(oldUri.getScheme(), oldUri.getAuthority(),
            oldUri.getPath(), newQueryParams, oldUri.getFragment());
    return newUri;
}

编辑1:

Pattern p = Pattern.compile("HREF=\"(.*?)\"");

这有效。但我希望它与大小写无关。 Href、HRef、href、hrEF 等都应该可以工作。

此外，如果我的文本有多个 URL，我该如何处理。

编辑2:

一些进展。

Pattern p = Pattern.compile("href=\"(.*?)\"");
Matcher m = p.matcher(text);
String url = null;
while (m.find()) {
  url = m.group(1);
  System.out.println(url);
}

这可以处理多个 URL 的情况。

最后一个悬而未决的问题是，如何获取标签并将原始文本中的 href 标签替换为 URL 和标签。

编辑3:

通过多个 URL 情况，我的意思是给定文本中存在多个 URL。

String text = "Some content which contains link as <A HREF=\"/relative-path/fruit.cgi?param1=abc&param2=xyz\">URL Label</A> and some text after it and another link <A HREF=\"/relative-path/vegetables.cgi?param1=abc&param2=xyz\">URL2 Label</A> and some more text";

Pattern p = Pattern.compile("href=\"(.*?)\"", Pattern.CASE_INSENSITIVE);
Matcher m = p.matcher(text);
String url = null;
while (m.find()) {
 url = m.group(1); // this variable should contain the link URL
 url = appendBaseURI(url);
 url = appendQueryParams(url, "license=ABCXYZ");
 System.out.println(url);
}

Answer 1

public static void main(String args[]) {
    String text = "Some content which contains link as <A HREF=\"/relative-path/fruit.cgi?param1=abc&param2=xyz\">URL Label</A> and some text after it and another link <A HREF=\"/relative-path/vegetables.cgi?param1=abc&param2=xyz\">URL2 Label</A> and some more text";
    text = StringEscapeUtils.unescapeHtml4(text);
    Pattern p = Pattern.compile("<a href=\"(.*?)\">(.*?)</a>", Pattern.CASE_INSENSITIVE);
    Matcher m = p.matcher(text);
    while (m.find()) {
        text = text.replace(m.group(0), cleanUrlPart(m.group(1), m.group(2)));
    }
    System.out.println(text);
}

private static String cleanUrlPart(String url, String label) {
    if (!url.startsWith("http") && !url.startsWith("www")) {
        if (url.startsWith("/")) {
            url = "http://www.google.com" + url;
        } else {
            url = "http://www.google.com/" + url;
        }
    }
    url = appendQueryParams(url, "myParam=pqr").toString();
    if (label != null && !label.isEmpty()) url += " (" + label + ")";
    return url;
}

输出

Some content which contains link as http://www.google.com/relative-path/fruit.cgi?param1=abc&param2=xyz&myParam=pqr (URL Label) and some text after it and another link http://www.google.com/relative-path/vegetables.cgi?param1=abc&param2=xyz&myParam=pqr (URL2 Label) and some more text