c++ - 如何通过在for循环中旋转一个方向来获取采样点？

Question

我需要遍历给定数量的采样点。这些采样点是表示方向的归一化 vector 。他们应该用代码计算它们。从前向 vector 1, 0 开始，我想绕原点旋转，以便得出给定的方向数。

for(int i = 0; i < number_of_sampling_points; ++i)
{
    // get direction vector based on i and number_of_sampling_points
    // ...
}

例如，在循环中 number_of_sampling_points 是 4 我想得到值对 1, 0, 0, 1, -1, 0, 0, -1。顺序无关紧要。

Answer 1

试试这个:

const double PI = 3.14159265358979323846;
const int number_of_sampling_points = 4;
for (int i = 0; i < number_of_sampling_points; ++i)
{
    const double a = PI * 2 * (1.0 - i) / number_of_sampling_points;

    double x = sin(a);
    double y = cos(a);

    cout << "(" << x << " , " << y << ")" << endl;
}

输出(四舍五入):

(1 , 0)
(0 , 1)
(-1 , 0)
(0 , -1)