android - 在 android 中匹配来自 SMS 的精确 7 位数字但它也采用其他数字

Question

no> 在 android 中匹配来自 SMS 的精确 7 位数字但它无法正常工作。

actually I need exact 7 digits from SMS(like MMID have 7 digit).

public class IncomingSms extends BroadcastReceiver {

final SmsManager sms = SmsManager.getDefault();

public void onReceive(Context context, Intent intent) {

    final Bundle bundle = intent.getExtras();

    try {

        if (bundle != null) {

            final Object[] pdusObj = (Object[]) bundle.get("pdus");

            for (int i = 0; i < pdusObj.length; i++) {

                SmsMessage currentMessage = SmsMessage.createFromPdu((byte[]) pdusObj[i]);
                String phoneNumber = currentMessage.getDisplayOriginatingAddress();
                currentMessage.getOriginatingAddress();

                phoneNumber.equals("xxxxxxxxx");

                String message = currentMessage.getDisplayMessageBody();
                String s = null ;
                String e = "\\d{7}";
                Pattern p = Pattern.compile(e);
                Matcher m = p.matcher(message);


                while (m.matches())
                {
                    s = m.group(0);

                    int duration = Toast.LENGTH_LONG;
                    Toast toast = Toast.makeText(context, "senderNum: "+ phoneNumber + ",  mmid: "+s, duration);
                    toast.show();   

                }
            } 
        } 

    } 
    catch (Exception e)
    {
        Log.e("SmsReceiver", "Exception smsReceiver" +e);
    }
}    

In SMS message: your no alloted for the no xxxxxx01019015xx is 8435753.

its taking value from this word (xxxxxx01019015xx) like 0101901

But toast showing 0101901 and 8435753

Answer 1

使用 m.matches() 而不是 m.find() 作为 Matched#matches 方法确保匹配完整的输入正则表达式。另一方面，Matched#find 使用您的正则表达式(部分)匹配任何可能的内容。

最好像这样在正则表达式中使用 anchor :

Pattern p = Pattern.compile("^\\d{7}$");