C++ : integer constant is too large for its type

Question

我需要暴力破解一年来进行练习。编译器不断抛出此错误:

bruteforceJS12.cpp:8:28: warning: integer constant is too large for its type [enabled by default]

我的代码是:

#include <iostream>

using namespace std;

int main(){

    unsigned long long year(0);
    unsigned long long result(318338237039211050000);
    unsigned long long pass(1337);

    while (pass != result)
    {
    for (unsigned long long i = 1; i<= year; i++)
        {

        pass += year * i * year;

        }

        cout << "pass not cracked with year = " << year << endl;
        ++year;

    }

        cout << "pass cracked with year = " << year << endl;
}

请注意，我已经尝试使用 unsigned long long result(318338237039211050000ULL);

我使用的是 gcc 4.8.1 版

编辑:

这是使用 InfInt 库的更正版本 http://code.google.com/p/infint/

#include <iostream>
#include "InfInt.h"

using namespace std;

int main(){

    InfInt year = "113";
    InfInt result = "318338237039211050000";
    InfInt pass= "1337";

    while (pass != result)
    {
    for (InfInt i = 1; i<= year; i++)
        {

        pass += year * i * year;

        }

        cout << "year = " << year << "  pass = " << pass <<  endl;
        ++year;

    }

        cout << "pass cracked with year = " << year << endl;
}

Answer 1

找出系统数字限制的快速方法是使用 std::numeric_limits .运行以下代码时系统上的输出:

#include <iostream>
#include <limits>

int main()
{   
     std::cout << "ull\t"
              << std::numeric_limits<unsigned long long>::lowest() << '\t'
              << std::numeric_limits<unsigned long long>::max() << std::endl ;
}

是:

ull 0   18446744073709551615

我们可以看到最大值肯定小于你的字面值:

 18446744073709551615
 318338237039211050000

所以你的整数字面值对于 unsigned long long 类型来说太大了。