c++ - 反向字符串脚本给出运行时错误

Question

我已尽力修复我的逻辑，但我无法检测到错误。我不能使用 [] 或任何其他高级功能，因为我还没有介绍它们。如果可以，请告诉我我的错误。请不要给我负分，因为我已经尽力了，我的错误没有意义!谢谢。

这个脚本应该反转输入字符串:例如:hi 到 ih。

#include<iostream>
#include<string>
#include<cstdlib>
using namespace std;

void ReverseString(string &aString);

int main(){
    string info;
    cout << "What's your string?" << endl;
    getline(cin, info);
    cout << info << " compare with: " << endl;
    ReverseString(info);
    cout << info << endl;
    system("pause");
    return 0;
}

void ReverseString(string &aString)
{

    for(int i = 0; i < aString.length(); i++)
    {

        int u = aString.length() - 1 - i;
        string temp = "";
        temp += aString.at(aString.length() - 1 - i); 
        if(u == 0 )/* when aString.length() - 1 - i == 0, the last char will have been processed*/
        {
        aString = temp; /*store temp into aString; when its value changes, it is passed     into info's value*/
        }


    }

}

Answer 1

您的问题是，每次您在 ReverseString() 中运行 for 循环时，您都会重新初始化您的 temp 变量，删除您已经拥有的所有内容保存在字符串中。如果我对 ReverseString 函数执行此操作，您的程序将按预期运行:

void ReverseString(string &aString)
    string temp = "";

    for(int i = 0; i < aString.length(); i++)
    {

        int u = aString.length() - 1 - i;
        temp += aString.at(aString.length() - 1 - i); 
        if(u == 0 )/* when aString.length() - 1 - i == 0, the last char will have been processed*/
        {
        aString = temp; /*store temp into aString; when its value changes, it is passed     into info's value*/
        }