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c++ - 我需要复制构造函数吗?以及如何使用复制构造函数将 const 对象复制到非 const 对象

转载 作者:行者123 更新时间:2023-11-30 01:54:57 24 4
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目标:我必须将一个对象复制到另一个对象中。

我想在不使用赋值或复制构造函数的情况下复制它,但它无法编译。所以我使用了复制构造函数/赋值运算符。

问题
.现在我有 2 个问题?

1) 我真的需要复制构造函数和赋值运算符吗?据我所知,我没有在成员变量中使用任何指针,所以不需要使用复制构造函数?

然后我的对象是一个指针,所以我可能需要它吗?

2) 如果我下面的代码是正确的,为什么我会收到如下所示的错误
无法从“const Home_instance *”转换为“Home_instance *”

home_data.h

struct home_data
{
QString area_address_;
QVector<QString> home_numbers_;
QMap< QString, QList<QByteArray> > area_to_home_mapping;
};


Home_instance.h

class Home_instance : public QObject
{
Q_OBJECT

public:
Home_instance( const Home_data& data, QObject* parent_p = 0 );
Home_instance();
Home_instance( const Home_instance& rhs );
Home_instance& operator=( const Home_instance& rhs );
~Home_instance();
// some otehr functions

private:
Home_data data_;


}

Home_instance.cpp

//constructors

Firmware_instance::Home_instance( )
{
}

Home_instance::Home_instance( const Home_data& data, QObject* parent_p )
: QObject( parent_p ),
data_ ( data )
{}

Home_instance::Home_instance( const Home_instance& rhs )
{
data_.ip_address_ = rhs.data_.ip_address_;
data_.serial_numbers_ = rhs.data_.serial_numbers_;
data_.serial_to_slot_mapping = rhs.data_.serial_to_slot_mapping;

}

Home_instance& Home_instance::operator=( const Home_instance& rhs )
{
data_.ip_address_ = rhs.data_.ip_address_;
data_.serial_numbers_ = rhs.data_.serial_numbers_;
data_.serial_to_slot_mapping = rhs.data_.serial_to_slot_mapping;
return *this;
}

Home_instance::~Home_instance()
{
// do we actually need destructor ?
}

// in some other Dialog window say Council.h &cpp


class Council
{

// some other variable decl
private:
Home_instance* Home_instance_p_;
Home_data Home_data_p_;

}


in council.cpp

// in constructor

{


connect( udp_p_, SIGNAL( discovered_Home( const Home_instance* ) ), this, SLOT( new_Home( const Home_instance* ) ) );
}


// in function new_home

void Council::new_home( const Home_instance* Home_old_instance )

{

// bla bla

Home_instance_p_ = Home_old_instance; // error can not convert from 'const Home_instance *' to 'Home_instance *'
}

谢谢

最佳答案

这个

Home_instance_p_  =     Home_old_instance;

不复制对象,它尝试复制指针。

你想要

Home_instance_p_ = new Home_instance(*Home_old_instance);

然后删除~Council中的Home_instance_p_

关于c++ - 我需要复制构造函数吗?以及如何使用复制构造函数将 const 对象复制到非 const 对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21284896/

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