java - 关于 while 循环的问题以及如何重新提出 y/n 问题

Question

我正在创建将一个单词(由用户获得)翻译成 Pig Latin 的代码。我的代码运行得非常好，除了一件事。我希望用户输入“y”或“n”来确定代码是否运行。我正在使用 while 循环来确定要执行的内容。如果用户输入除上面列出的两个之外的任何内容，我希望它再次询问。目前，我有一个占位符，可以让用户愚蠢并重新启动代码。我怎样才能做到这一点？非常感谢大家!

public static void main(String[] args) 
{

    Scanner stdIn = new Scanner(System.in);
    String playGame;
    String word;

    // Explains what the program does \\
    System.out.println("Welcome to Coulter's Pig Latin Translator!");
    System.out.println("If you choose to play, you will be asked to type a word which will be translated.");
    System.out.println();

    // Asks the user if they would like to play and checks 'y' or 'n' using a while statement \\
    System.out.println("Would you like to play? [y/n]: ");
    playGame = stdIn.next();

    while(playGame.equals("y") || playGame.equals("n")) // While expression that will check if the user enters a 'y' or 'n'
    {
        if (playGame.equals("y")) // Executes if the user entered 'y'
        {
            System.out.println("Please enter the word that you would like to translate: ");
            word = stdIn.next(); // Receives the word the user wishes to translate

            System.out.println("_______________________________________________________");

            System.out.println();
            System.out.println("You entered the word: " + word); // Displays what the user entered

            System.out.println();
            System.out.println("Translation: " + solve(word)); // Displays the solved word

            System.out.println();
            System.out.println("Thanks for playing!"); // 
            return; // Ends the code

        }

        else if(playGame.contentEquals("n")) // Executes if the user entered 'n'
        {
            System.out.println("That's okay! Come back when you want to.");
            return; // Ends the code
        }   
    }

    System.out.println("_______________________________________________________");
    System.out.println("Don't be silly. Restart and type either 'y' or 'n'"); // Tells the user to restart if they entered anything but 'y' or 'n'

}

// Word translator code using a new static\\
public static String solve (String word) 
{
    String temp = word.toLowerCase();
    char[] vowels = {'a', 'e', 'i', 'o', 'u'}; // Stores vowels in an array
    char first = temp.charAt(0); // Defines first character for later use

    for (int i = 0; i < vowels.length; i++) // Looks for first vowel to replace it
    {
        if (first == vowels[i]) 
        {
            return word + "way"; // Replaces checked vowel
        }
    }

    word = word.substring(1); // Returns the string to the end of the word
    word += first + "ay";


    return word; // Returns the translated word to the program above
}

}

Answer 1

好吧，您在这里要求输入:

playGame = stdIn.next();

只需进入你的循环即可:

playOn = true;
while(playOn) {
  playGame = stdIn.next();
  if ( y ) { ... play 
  } else {
    if ( n ) { ... dont play, set playOn = false
    } else {
      ... ask again
    } 
  }

以上内容只是作为灵感，并指出:这里真正重要的是你得到了 if/else 链，以及相应的“ block ”。您需要完全在第一个“else” block 内另一个 if/else!