android - 在路径 : DexPathList 上找不到类

Question

在运行并收到短信后，我在此代码中使用了接收器，显示此错误。我尝试一些事情。我创建新项目并再次添加文件。删除bin文件。清理并重新启动项目。但它不能解决错误。有什么可以解决这个错误。我真的解决不了。

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="blocker.activity"
android:versionCode="1"
android:versionName="1.0" >
<uses-permission android:name="android.permission.READ_PHONE_STATE"/>
<uses-permission android:name="android.permission.CALL_PHONE"/>
<uses-permission android:name="android.permission.READ_CONTACTS" /> 
<uses-permission android:name="android.permission.MODIFY_PHONE_STATE" />
<uses-permission android:name="android.permission.RECEIVE_SMS"></uses-permission>
<uses-permission android:name="android.permission.READ_SMS" />
<uses-permission android:name="android.permission.SEND_SMS"></uses-permission>

<uses-sdk android:minSdkVersion="8" />

<application
    android:icon="@drawable/ic_launcher"
    android:label="@string/app_name" >
    <activity

        android:name=".FirstPage"
        android:label="@string/app_name" >
        <intent-filter>
            <action android:name="android.intent.action.MAIN" />

            <category android:name="android.intent.category.LAUNCHER" />
        </intent-filter>
    </activity>

 <receiver android:name=".receiver.SMSReceiver" android:enabled="true">
<intent-filter android:priority="999">
    <action android:name="android.provider.Telephony.SMS_RECEIVED" />
</intent-filter>
</receiver>


    <activity

        android:name=".Search"
        android:label="@string/app_name" >

    </activity>

    <activity

        android:name=".BlockActivity"
        android:label="@string/app_name" >

    </activity>


    <activity
        android:name=".SmsFilter"
        android:label="@string/app_name" >

    </activity>


    <activity
        android:name=".CustomAdapter"
        android:label="@string/app_name" >

    </activity>
    </application>

  </manifest>

错误:

属性:

短信接收类:

public class SmsFilter extends BroadcastReceiver {

@Override
public void onReceive(Context context, Intent intent) {




    if (intent.getAction().equals("android.provider.Telephony.SMS_RECEIVED")) {
        Bundle extras = intent.getExtras();
        if (extras != null) {
            Object[] pdus = (Object[])extras.get("pdus");

            if (pdus.length < 1) return; // Invalid SMS. Not sure that it's possible.

            StringBuilder sb = new StringBuilder();
            String sender = null;
            for (int i = 0; i < pdus.length; i++) {
                SmsMessage message = SmsMessage.createFromPdu((byte[]) pdus[i]);
                if (sender == null) sender = message.getOriginatingAddress();
                String text = message.getMessageBody();
                if (text != null) sb.append(text);
            }

            Log.i("LOG: ", "sms recived");
            Log.i("LOG: ", sender);



            if (sender != null &&  Search.search(sender)==true) {


                 abortBroadcast();

            }
            return;
        }
    }

    // ...
}




}

Answer 1

请再次检查接收者的名称和您在 list 接收者中声明的类名。

在 java 文件中类名是-SmsFilter extends BroadcastReceiver

SmsFilter extends BroadcastReceiver

如您所见，名称是 Sm​​sFilter，但在您的 list 文件中，您将其声明为 SMSReceiver

名称不匹配。将您的 list 编辑为类似这样的内容-

<receiver android:name=".receiver.SmsFilter" android:enabled="true">
<intent-filter android:priority="999">
<action android:name="android.provider.Telephony.SMS_RECEIVED" />
</intent-filter>
</receiver>

希望对你有帮助