java - 为什么子类getter返回其父类(super class)的属性？

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                                9个月前关闭。
            
                    
我在考试时有这个确切的问题：

以下程序显示什么，为什么？

class Base {
    private String className = "Base";
    public String name() { return this.className; }
}

class Derived extends Base {
    private String className = "Derived";
}

public class Test {
    public static void main(String[] args) {
        System.out.println(new Derived().name());
    }   
}

所以输出是“ Base”，但是我想知道为什么。吸气剂 name()是否不应该返回子类属性？

最佳答案

正如安迪·特纳（Andy Turner）所说，类字段不是多态的。但是此代码将实现您的期望：

class Base {
    public String name() { return this.func(); }
    public String func(){return "Base";}
}

class Derived extends Base {
    public String func(){return "Derived";}
}

public class Test {
    public static void main(String[] args) {
        System.out.println(new Derived().name());
    }
}

关于java - 为什么子类getter返回其父类(super class)的属性？ ，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/56211068/

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Answer 1

正如安迪·特纳（Andy Turner）所说，类字段不是多态的。但是此代码将实现您的期望：

class Base {
    public String name() { return this.func(); }
    public String func(){return "Base";}
}

class Derived extends Base {
    public String func(){return "Derived";}
}

public class Test {
    public static void main(String[] args) {
        System.out.println(new Derived().name());
    }
}